RESOLU\u00c7\u00c3O:<\/strong><\/p>\nNesta sequ\u00eancia temos uma multiplica\u00e7\u00e3o por 0,9 (de 100.000 para 90.000), depois outra multiplica\u00e7\u00e3o por 0,9 (de 90.000 para 81.000), e assim por diante.<\/p>\n
Preenchendo os pr\u00f3ximos termos, temos:<\/p>\n
100.000 – 90.000 – 81.000 – 72.800 – 65.520 – 58.968 – 53.071,2 – …<\/p>\n
Veja que o 7\u00ba termo \u00e9 o primeiro N\u00c3O INTEIRO. Assim, o segundo termo n\u00e3o inteiro ser\u00e1, certamente, o 8\u00ba.<\/p>\n
Resposta: D<\/strong><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0Considere a afirma\u00e7\u00e3o…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nTemos a condicional P–>Q no enunciado, onde:<\/p>\n
P = n\u00e3o contratei um empr\u00e9stimo com juros maiores \u00a0do que antes<\/p>\n
Q = pagarei um montante maior<\/p>\n
A sua nega\u00e7\u00e3o \u00e9 P e ~Q, onde:<\/p>\n
~q = N\u00c3O pagarei um montante maior<\/p>\n
Escrevendo a nega\u00e7\u00e3o:<\/p>\n
“N\u00e3o contratei um empr\u00e9stimo com juros maiores do que antes E N\u00c3O pagarei um montante maior<\/p>\n
Resposta: D<\/strong><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0Uma motocicleta foi vendida…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nO lucro foi de 8% do pre\u00e7o de venda. Ou seja,<\/p>\n
Lucro = 8% x 18500 = 0,08 x 18500 = 8 x 185 = 1480 reais<\/p>\n
O custo \u00e9, portanto:<\/p>\n
Custo = pre\u00e7o de venda – lucro<\/p>\n
Custo = 18500 – 1480 = 17020 reais<\/p>\n
Resposta: E<\/strong><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0Em um programa de amplia\u00e7\u00e3o…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nAs quantidades de livros compradas podem ser obtidas dividindo-se o custo total pelo custo unit\u00e1rio:<\/p>\n
Livros do primeiro grupo = 960 \/ 24 = 40<\/p>\n
Livros do segundo grupo = 2×960 \/ 16 = 120<\/p>\n
Portanto, foram comprados 120 + 40 = 160 livros ao custo total de 960 + 2×960 = 2880 reais. O custo unit\u00e1rio m\u00e9dio \u00e9:<\/p>\n
Custo unit\u00e1rio m\u00e9dio = custo total \/ quantidade = 2880\/160 = 18 reais<\/p>\n
Resposta: A<\/strong><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0Em um caminho h\u00e1…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nVeja que Roberto dele levar a 1\u00aa caixa at\u00e9 a posi\u00e7\u00e3o da 11\u00aa caixa (que fica no meio das 21), caminhando com ela 10×10 = 100 metros. Em seguida ele deve retornar 90 metros at\u00e9 a 2\u00aa caixa, lev\u00e1-la 90 metros at\u00e9 a 11\u00aa, retornar 80 metros at\u00e9 a 3\u00aa caixa, lev\u00e1-la 80 metros at\u00e9 a 11\u00aa, e assim por diante. Temos a soma de dist\u00e2ncias:<\/p>\n
100 + 90×2 + 80×2 + 70×2 + 60×2 + 50×2 + 40×2 + 30×2 + 20×2 + 10×2 = 1000 metros<\/p>\n
Feito isso, ser\u00e1 preciso andar 100 metros para chegar at\u00e9 a 21\u00aa caixa. At\u00e9 aqui temos 1000 + 100 = 1100 metros<\/p>\n
A partir daqui recome\u00e7a um processo similar ao anterior, em que Roberto percorrer\u00e1 1000 metros. Ao todo, teremos 1000 + 1100 = 2100 metros.<\/p>\n
Resposta: E<\/strong><\/p>\nMATEM\u00c1TICA FINANCEIRA<\/strong><\/span><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0Jo\u00e3o emprestou…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nTemos um empr\u00e9sitmo de C = 23500 reais, juros simples de j = 4% ao ano, prazo de t = 3 anos. Os juros pagos s\u00e3o de:<\/p>\n
<\/p>\n
J = C x j x t<\/p>\n
J = 23500 x 0,04 x 3<\/p>\n
J = 235 x 4 x 3<\/p>\n
J = 235 x 12<\/p>\n
J = 2820 reais<\/p>\n
Resposta: B<\/strong><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0O montante de um empr\u00e9stimo…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nTemos um prazo de t = 4 anos, capital inicial C = 20000 reais, juros compostos de j = 10% ao ano. O montante final \u00e9:<\/p>\n
M = C x (1+j)t<\/sup><\/p>\nM = 20000 x (1+0,10)4<\/sup><\/p>\nM = 20000 x 1,14<\/sup><\/p>\nM = 20000 x 1,4641<\/p>\n
M = 2 x 14641<\/p>\n
M = 29282 reais<\/p>\n
Resposta: C<\/strong><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0Um empr\u00e9stimo foi…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nTemos taxa nominal de 6% ao trimestre com capitaliza\u00e7\u00e3o mensal, o que corresponde \u00e0 taxa efetiva de 6% \/ 3 = 2% ao m\u00eas, afinal temos tr\u00eas meses em um trimestre.<\/p>\n
A taxa efetiva trimestral \u00e9 obtida pelo m\u00e9todo da equival\u00eancia:<\/p>\n
(1 + j)t<\/sup> = (1 + jeq<\/sub>)teq<\/sup><\/p>\n(1 + 0,02)t<\/sup> = (1 + jeq<\/sub>)teq<\/sup><\/p>\n <\/p>\n
Lembrando que teq = 1 trimestre corresponde a t = 3 meses:<\/p>\n
(1 + 0,02)3<\/sup> = (1 + jeq<\/sub>)1<\/sup><\/p>\n(1,02)3<\/sup> = 1 + jeq<\/sub><\/p>\n1,0612 = 1 + jeq<\/sub><\/p>\n1,0612 – 1 = jeq<\/sub><\/p>\n0,0612 = jeq<\/sub><\/p>\n6,12% ao trimestre = jeq<\/sub><\/p>\nResposta: E<\/strong><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0Um empr\u00e9stimo com juros…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nPodemos descobrir a taxa de juros anual que equivale a j = 1,2% ao m\u00eas. Fazemos isso com a f\u00f3rmula que iguala os fatores de acumula\u00e7\u00e3o de capital:<\/p>\n
(1 + j)t<\/sup> = (1 + jeq<\/sub>)teq<\/sup><\/p>\n(1 + 0,012)t<\/sup> = (1 + jeq<\/sub>)teq<\/sup><\/p>\nLembrando que t = 12 meses corresponde a teq = 1 ano, temos:<\/p>\n
(1 + 0,012)12<\/sup> = (1 + jeq<\/sub>)1<\/sup><\/p>\n(1,012)12<\/sup> = 1 + jeq<\/sub><\/p>\n(1,012)12<\/sup>\u00a0 – 1 = jeq<\/sub><\/p>\n <\/p>\n
Na express\u00e3o acima, vamos obter a taxa de juros na forma decimal. Para obt\u00ea-la na forma percentual, basta multiplic\u00e1-la por 100%, ficando:<\/p>\n
((1,012)12<\/sup>\u00a0– 1) x 100% = jeq<\/sub><\/p>\nResposta: C<\/strong><\/p>\nFCC – FUNAPE – 2017)<\/strong>\u00a0A quantia de R$41.212,04…<\/p>\nRESOLU\u00c7\u00c3O:<\/strong><\/p>\nTemos o montante M =\u00a041.212,04, o capital inicial C = 40.000 e prazo t = 3 meses. Podemos descobrir a taxa de juros na f\u00f3rmula:<\/p>\n
M = C x (1+j)t<\/sup><\/p>\n41212,04 = 40000 x (1+j)3<\/sup><\/p>\n41212,04 \/ 40000 = (1+j)3<\/sup><\/p>\n4,121204 \/ 4 = (1+j)3<\/sup><\/p>\n1,030301 = (1+j)3<\/sup><\/p>\n <\/p>\n
Neste ponto, o melhor que voc\u00ea faz \u00e9 testar as alternativas de resposta. Come\u00e7ando com j = 1,0%, temos:<\/p>\n
(1 + 1%)3\u00a0<\/sup>= 1,01 x 1,01 x 1,01 = 1,0201 x 1,01 = 1,030301<\/p>\n <\/p>\n
Fica claro que o gabarito \u00e9 j = 1%.<\/p>\n
Resposta: A<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"Caros alunos, Vejam em anexo a resolu\u00e7\u00e3o das quest\u00f5es de Racioc\u00ednio L\u00f3gico-Matem\u00e1tico da prova da FUNAPE, ocorrida neste \u00faltimo final de semana. Caso voc\u00eas queiram ver os enunciados, basta acessar as imagens aqui: PROVA FUNAPE PARTE 1 PROVA FUNAPE PARTE 2 PROVA FUNAPE PARTE 3 PROVA FUNAPE PARTE 4 RACIOC\u00cdNIO L\u00d3GICO FCC – […]<\/p>\n","protected":false},"author":48,"featured_media":43262,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"post_tipo":"article","footnotes":""},"categories":[1],"tags":[],"tax_estado":[],"class_list":["post-87816","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cursos-e-concursos"],"acf":[],"yoast_head":"\n
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Caso voc\u00eas queiram ver os enunciados, basta acessar as imagens aqui: PROVA FUNAPE PARTE 1 PROVA FUNAPE PARTE 2 PROVA FUNAPE PARTE 3 PROVA FUNAPE PARTE 4 RACIOC\u00cdNIO L\u00d3GICO FCC – […]","og_url":"https:\/\/www.estrategiaconcursos.com.br\/blog\/raciocinio-logico-e-mat-financeira-funape-banca-fcc-prova-resolvida\/","og_site_name":"Estrat\u00e9gia Concursos","article_published_time":"2017-09-04T18:23:49+00:00","article_modified_time":"2018-09-21T18:42:34+00:00","og_image":[{"width":400,"height":267,"url":"https:\/\/dhg1h5j42swfq.cloudfront.net\/2016\/07\/09202054\/gabarito-e1509444514343.jpeg","type":"image\/jpeg"}],"author":"Coordena\u00e7\u00e3o","twitter_card":"summary_large_image","twitter_creator":"@EstratConcursos","twitter_site":"@EstratConcursos","twitter_misc":{"Escrito por":"Coordena\u00e7\u00e3o","Est. tempo de leitura":"4 minutos"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"NewsArticle","@id":"https:\/\/www.estrategiaconcursos.com.br\/blog\/raciocinio-logico-e-mat-financeira-funape-banca-fcc-prova-resolvida\/#article","isPartOf":{"@id":"https:\/\/www.estrategiaconcursos.com.br\/blog\/raciocinio-logico-e-mat-financeira-funape-banca-fcc-prova-resolvida\/"},"author":{"name":"Coordena\u00e7\u00e3o","@id":"https:\/\/www.estrategiaconcursos.com.br\/blog\/#\/schema\/person\/cdad40b5818eb228a838461fcd656da7"},"headline":"Racioc\u00ednio L\u00f3gico e Mat. 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