{"id":821560,"date":"2021-07-25T19:23:28","date_gmt":"2021-07-25T22:23:28","guid":{"rendered":"https:\/\/www.estrategiaconcursos.com.br\/blog\/?p=821560"},"modified":"2021-07-25T19:24:11","modified_gmt":"2021-07-25T22:24:11","slug":"gabarito-extraoficial-itep-rn-quimica","status":"publish","type":"post","link":"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-itep-rn-quimica\/","title":{"rendered":"Gabarito Extraoficial ITEP RN &#8211; Qu\u00edmica"},"content":{"rendered":"\n<p id=\"block-48b5fcf9-0ddf-4e35-9c5b-1092f2c2616d\">Ol\u00e1, pessoal. Tudo bem?<\/p>\n\n\n\n<p id=\"block-fe2fae61-12a9-4928-831e-799ce15a65e3\">Neste artigo faremos uma breve corre\u00e7\u00e3o da prova de<strong>\u00a0Qu\u00edmica <\/strong>aplicada para o cargo de\u00a0<strong>Perito Criminal <\/strong>do ITEP-RN. Vale ressaltar que essa corre\u00e7\u00e3o \u00e9 EXTRAOFICIAL, sendo necess\u00e1rio aguardar o gabarito preliminar da banca para confirmar o seu desempenho.<\/p>\n\n\n\n<p id=\"block-5139e1b6-4e62-468f-8137-d82dd9d2d565\"><em>Vamos l\u00e1?<\/em><\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"block-b7f520bd-8b49-44fe-83d5-f68b89378910\">CORRE\u00c7\u00c3O EXTRAOFICIAL &#8211; CARGO: Perito Criminal<\/h2>\n\n\n\n<p><strong><span class=\"has-inline-color has-vivid-cyan-blue-color\">PROVA 4 &#8211; QU\u00cdMICA<\/span><\/strong><\/p>\n\n\n\n<p><strong><em><span class=\"has-inline-color has-vivid-purple-color\">91- Para uma determinada an\u00e1lise<\/span><\/em><\/strong><\/p>\n\n\n\n<p><strong>A) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>B) CERTO. Solu\u00e7\u00e3o de tamp\u00e3o, utiliza-se a equa\u00e7\u00e3o de Henderson-Hasselbalch: pH = pKa + log([A-]\/[HA]).<\/strong><\/p>\n\n\n\n<p><strong>C) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>D) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong><em><span class=\"has-inline-color has-vivid-purple-color\">92- Assinale a alternativa<\/span><\/em><\/strong><\/p>\n\n\n\n<p><strong>A) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>B) CERTO. Ficamos entre a alternativa \u201cB\u201d e alternativa \u201cD\u201d, pois a resposta depende se a press\u00e3o aplicada nesse sistema \u00e9 maior ou menor que a press\u00e3o de vapor de CO2. Se a press\u00e3o for suficiente para deixar o CO2 na forma s\u00f3lida, poder\u00edamos entender que a alternativa correta seria a letra \u201cD\u201d pois caso n\u00e3o evapore o CO2, n\u00e3o tem como reagir com o \u00f3xido de c\u00e1lcio para recompor parte do carbonato de c\u00e1lcio. No entanto, caso pensarmos na press\u00e3o aplicada, uma parte do CO2 sublima, a\u00ed ter\u00edamos a letra \u201cB\u201d como correta, pois numa press\u00e3o maior que a constante de equil\u00edbrio, a rea\u00e7\u00e3o se desloca e mesmo que aja forma\u00e7\u00e3o do g\u00e1s carb\u00f4nico na forma gasosa, essa rea\u00e7\u00e3o estaria totalmente deslocada pela press\u00e3o aumentada para o lado do carbonato de c\u00e1lcio, de tal forma que uma press\u00e3o muito elevada impediria o carbonato de c\u00e1lcio de se decompor em \u00f3xido de c\u00e1lcio e g\u00e1s carb\u00f4nico. Ent\u00e3o, a resposta depende dessa press\u00e3o que n\u00e3o nos foi informada no enunciado.<\/strong><\/p>\n\n\n\n<p><strong>C) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>D) CERTO. Ficamos entre a alternativa \u201cB\u201d e alternativa \u201cD\u201d, pois a resposta depende se a press\u00e3o aplicada nesse sistema \u00e9 maior ou menor que a press\u00e3o de vapor de CO2. Se a press\u00e3o for suficiente para deixar o CO2 na forma s\u00f3lida, poder\u00edamos entender que a alternativa correta seria a letra \u201cD\u201d pois caso n\u00e3o evapore o CO2, n\u00e3o tem como reagir com o \u00f3xido de c\u00e1lcio para recompor parte do carbonato de c\u00e1lcio. No entanto, caso pensarmos na press\u00e3o aplicada, uma parte do CO2 sublima, a\u00ed ter\u00edamos a letra \u201cB\u201d como correta, pois numa press\u00e3o maior que a constante de equil\u00edbrio, a rea\u00e7\u00e3o se desloca e mesmo que aja forma\u00e7\u00e3o do g\u00e1s carb\u00f4nico na forma gasosa, essa rea\u00e7\u00e3o estaria totalmente deslocada pela press\u00e3o aumentada para o lado do carbonato de c\u00e1lcio, de tal forma que uma press\u00e3o muito elevada impediria o carbonato de c\u00e1lcio de se decompor em \u00f3xido de c\u00e1lcio e g\u00e1s carb\u00f4nico. Ent\u00e3o, a resposta depende dessa press\u00e3o que n\u00e3o nos foi informada no enunciado.<\/strong><\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong><em><span class=\"has-inline-color has-vivid-purple-color\">93- A depend\u00eancia da cin\u00e9tica<\/span><\/em><\/strong><\/p>\n\n\n\n<p><strong>A) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>B) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>C) CERTO. Temos um comportamento de reta quando relacionado o ln k versus&nbsp; 1\/T.<\/strong><\/p>\n\n\n\n<p><strong>D) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong><em><span class=\"has-inline-color has-vivid-purple-color\">94- Considere uma mistura<\/span><\/em><\/strong><\/p>\n\n\n\n<p><strong>A) CERTO. Necess\u00e1rio usar a quantidade de mols que \u00e9 diretamente proporcional ao n\u00famero de mol\u00e9culas.<\/strong><\/p>\n\n\n\n<p><strong>B) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>C) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>D) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong><em><span class=\"has-inline-color has-vivid-purple-color\">95- A rea\u00e7\u00e3o entre<\/span><\/em><\/strong> (&#8230;)<\/p>\n\n\n\n<p><strong>A) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>B) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>C) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>D) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>E) CERTO.<\/strong><\/p>\n\n\n\n<p><strong><em><span class=\"has-inline-color has-vivid-purple-color\">96- Sob condi\u00e7\u00f5es<\/span><\/em><\/strong> (&#8230;)<\/p>\n\n\n\n<p><strong>A) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>B) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>C) CERTO. \u00c9 necess\u00e1rio entender o potencial padr\u00e3o de quem reduz, menos o potencial padr\u00e3o de quem oxida.<\/strong><\/p>\n\n\n\n<p><strong>D) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO.<\/p>\n\n\n\n<p><em><span class=\"has-inline-color has-vivid-purple-color\"><strong>97- Uma solu\u00e7\u00e3o<\/strong> (&#8230;)<\/span><\/em><\/p>\n\n\n\n<p><strong>A) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>B) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>C) CERTO<\/strong>. <strong>Necess\u00e1rio utilizar a l\u00f3gica do KPS.<\/strong><\/p>\n\n\n\n<p><strong>D) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO.<\/p>\n\n\n\n<p><em><span class=\"has-inline-color has-vivid-purple-color\"><strong>98- O sulfeto<\/strong> (&#8230;)<\/span><\/em><\/p>\n\n\n\n<p><strong>A) <\/strong>ERRADO. F\u00f3rmula incorreta.<\/p>\n\n\n\n<p><strong>B) <\/strong>ERRADO. F\u00f3rmula incorreta.<\/p>\n\n\n\n<p><strong>C) CERTO.<\/strong><\/p>\n\n\n\n<p><strong>D) <\/strong>ERRADO. F\u00f3rmula incorreta.<\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO. N\u00e3o tem forma\u00e7\u00e3o de enxofre.<\/p>\n\n\n\n<p><em><span class=\"has-inline-color has-vivid-purple-color\"><strong>99- Foram dissolvidos<\/strong> (&#8230;)<\/span><\/em><\/p>\n\n\n\n<p><strong>A) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>B) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>C) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>D) CERTO.<\/strong><\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO.<\/p>\n\n\n\n<p><em><span class=\"has-inline-color has-vivid-purple-color\"><strong>100- Assinale a alternativa<\/strong> (&#8230;)<\/span><\/em><\/p>\n\n\n\n<p><strong>A) CERTO. Necess\u00e1rio entendimento da tabela peri\u00f3dica.<\/strong><\/p>\n\n\n\n<p><strong>B) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>C) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>D) <\/strong>ERRADO.<\/p>\n\n\n\n<p><strong>E) <\/strong>ERRADO.<\/p>\n\n\n\n<hr class=\"wp-block-separator\" id=\"block-e77dbb11-95b7-4583-aa6e-b5b33da0622f\"\/>\n\n\n\n<p id=\"block-46827b9f-4be3-46ac-9cc4-7838a5f4714a\">Esperamos que tenham ido bem!<\/p>\n\n\n\n<p id=\"block-cccbad17-4719-4490-9836-e4abb435144f\">Abra\u00e7os.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Ol\u00e1, pessoal. Tudo bem? Neste artigo faremos uma breve corre\u00e7\u00e3o da prova de\u00a0Qu\u00edmica aplicada para o cargo de\u00a0Perito Criminal do ITEP-RN. Vale ressaltar que essa corre\u00e7\u00e3o \u00e9 EXTRAOFICIAL, sendo necess\u00e1rio aguardar o gabarito preliminar da banca para confirmar o seu desempenho. Vamos l\u00e1? CORRE\u00c7\u00c3O EXTRAOFICIAL &#8211; CARGO: Perito Criminal PROVA 4 &#8211; QU\u00cdMICA 91- Para [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":821447,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"post_tipo":"article","footnotes":""},"categories":[220190],"tags":[],"tax_estado":[219983],"class_list":["post-821560","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-policial-peritos","tax_estado-rn"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.2 (Yoast SEO v27.2) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Gabarito Extraoficial ITEP RN - Qu\u00edmica<\/title>\n<meta name=\"description\" content=\"Confira neste artigo o gabarito e a corre\u00e7\u00e3o extraoficial das provas de Qu\u00edmica do concurso ITEP-RN.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-itep-rn-quimica\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Gabarito Extraoficial ITEP RN - Qu\u00edmica\" \/>\n<meta property=\"og:description\" content=\"Confira neste artigo o gabarito e a corre\u00e7\u00e3o extraoficial das provas de Qu\u00edmica do concurso ITEP-RN.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-itep-rn-quimica\/\" \/>\n<meta property=\"og:site_name\" content=\"Estrat\u00e9gia Concursos\" \/>\n<meta property=\"article:author\" content=\"https:\/\/www.facebook.com\/EstrategiaConcursos\" \/>\n<meta property=\"article:published_time\" content=\"2021-07-25T22:23:28+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2021-07-25T22:24:11+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/07\/25155728\/iteprn.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1200\" \/>\n\t<meta property=\"og:image:height\" content=\"628\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Coordena\u00e7\u00e3o\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@EstratConcursos\" \/>\n<meta name=\"twitter:site\" content=\"@EstratConcursos\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Coordena\u00e7\u00e3o\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"NewsArticle\",\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-itep-rn-quimica\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-itep-rn-quimica\/\"},\"author\":{\"name\":\"Coordena\u00e7\u00e3o\",\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/#\/schema\/person\/b4a388c97673c5f483d72185668afa1f\"},\"headline\":\"Gabarito Extraoficial ITEP RN &#8211; 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