{"id":787103,"date":"2021-07-05T12:57:33","date_gmt":"2021-07-05T15:57:33","guid":{"rendered":"https:\/\/blog-estrategia.mystagingwebsite.com\/blog\/?p=787103"},"modified":"2021-07-05T12:59:48","modified_gmt":"2021-07-05T15:59:48","slug":"gabarito-extraoficial-pc-pa-quimica","status":"publish","type":"post","link":"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-pc-pa-quimica\/","title":{"rendered":"Gabarito Extraoficial PC PA &#8211; Qu\u00edmica (Papiloscopista)"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Ol\u00e1, pessoal. Tudo bem?<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Neste artigo faremos uma breve corre\u00e7\u00e3o da prova de<strong> Qu\u00edmica <\/strong>aplicada para o cargo de <strong>Papiloscopista<\/strong> da Pol\u00edcia Civil do Par\u00e1. Vale ressaltar que essa corre\u00e7\u00e3o \u00e9 EXTRAOFICIAL, sendo necess\u00e1rio aguardar o gabarito preliminar da banca para confirmar o seu desempenho.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><em>Vamos l\u00e1?<\/em><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-prova-de-qu-mica-cargo-papiloscopista\">Prova de Qu\u00edmica- Cargo: PAPILOSCOPISTA<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><em><span class=\"has-inline-color has-luminous-vivid-orange-color\">56 \u2013 A ninidrina \u00e9 um reagente largamente usado na per\u00edcia papilosc\u00f3pica&#8230;<\/span><\/em><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra A: Ele pede a f\u00f3rmula molecular \u2013 errado, porque menciona a fun\u00e7\u00e3o alde\u00eddo.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra B \u2013 Gabarito \u2013 porque ele diz que n\u00e3o possui carbono assim\u00e9trico \u2013 aquele carbono que se liga a 4 ligantes diferentes.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra C: Errado, porque o carbono sp2 \u00e9 o carbono que faz dupla liga\u00e7\u00e3o \u2013 se contar, temos 8 carbonos do tipo sp2.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra D: Errado.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra E: Errado, porque o n\u00famero de liga\u00e7\u00f5es sigma \u00e9 diferente do pi.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>GABARITO: B<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><em><span class=\"has-inline-color has-luminous-vivid-orange-color\">57 \u2013 Considere a mistura de 100 mL de sulfeto de s\u00f3dio&#8230;<\/span><\/em><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Quest\u00e3o d\u00e1 uma s\u00e9rie de informa\u00e7\u00f5es que n\u00e3o \u00e9 importante para a solu\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Tem que usar a formula do Kps, concentra\u00e7\u00e3o dos produtos que estou solubilizando meu sal, dividido pelo reagente.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Kps = Concentra\u00e7\u00e3o de Chumbo x a Concentra\u00e7\u00e3o de Sulfeto.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>GABARITO: A<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><em><span class=\"has-inline-color has-luminous-vivid-orange-color\">58 \u2013 Muitas propriedades dos gases e l\u00edquidos refletem&#8230;<\/span><\/em><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Propriedades dos compostos \u2013 teria que comparar pontos de ebuli\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra A: Comparando Propano \u2013 hidrocarboneto com Alde\u00eddo \u2013 apresenta menor ponto de ebuli\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra B: Comparando Neopentano \u2013 is\u00f4mero do normalpentano \u2013 quando eu tenho ramifica\u00e7\u00e3o eu diminuo a intera\u00e7\u00e3o entre as mol\u00e9culas e o aumento e a volatilidade \u2013 reduzindo o ponto de ebuli\u00e7\u00e3o \u2013 errado.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra C: Fluor \u00e9 mais polar e interage mais fortemente uma mol\u00e9cula com a outra e, desta forma, o acido flor\u00eddico que apresenta o maior ponto de ebuli\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra D: Comparando uma acetona com 3 carbonos e, do outro lado, tenho etanol, deixando com caracter\u00edstica mais polar do que a acetona.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra E: Nosso gabarito: Porque o iodo est\u00e1 no 5\u00ba per\u00edodo na tabela peri\u00f3dica e tem um peso at\u00f4mico maior. A mol\u00e9cula de iodo \u00e9 mais pesada e por isso o ponto de ebuli\u00e7\u00e3o \u00e9 maior do que o cloro.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>GABARITO: E<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><em><span class=\"has-inline-color has-luminous-vivid-orange-color\">59 \u2013 Considera a c\u00e9lula voltaica descrita pela rea\u00e7\u00e3o entre&#8230;.<\/span><\/em><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">N\u00e3o deu a equa\u00e7\u00e3o completa &#8211; O aluno teria que ter conhecimento sobre semirrea\u00e7\u00e3o de oxida\u00e7\u00e3o, de redu\u00e7\u00e3o, como completar a semirrea\u00e7\u00e3o e depois achar a alternativa. Quociente da rea\u00e7\u00e3o \u00e9 calculado da mesma forma que uma constante de equil\u00edbrio \u2013 quem t\u00e1 do lado dos produtos e reagentes. A rea\u00e7\u00e3o entre o dicromato com o iodeto: do lado dos reagentes eu tenho que ter dicromato e iodeto no denominador dos quocientes. <strong>Das alternativas que temos, todas t\u00eam dicromato e iodeto<\/strong>. Diz tamb\u00e9m que causa amino\u00e1cido \u2013 tenho que ter do lado dos reagentes o H+, tamb\u00e9m exclu\u00edmos a letra B.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">S\u00f3lido solvente e os l\u00edquidos puros n\u00e3o entram na constante de equil\u00edbrio. Exclui letra A e B.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra C, D e E \u2013 ver balanceamento da rea\u00e7\u00e3o \u2013 dicromato: tenho dois cromos do lado debaixo, preciso ter dois do lado de cima.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Ou ser\u00e1 letra C ou E \u2013 a rea\u00e7\u00e3o produz iodo s\u00f3lidos \u2013 pra formar dois embaixo, eu tenho que ter na constante um  n\u00famero par de iodos. N\u00e3o tem como formar i2 a partir de 3 iodetos.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Ent\u00e3o a letra E \u2013 onde tenho 3 iodetos na parte debaixo n\u00e3o pode ser o gabarito.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Gabarito: C<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong><em><span class=\"has-inline-color has-luminous-vivid-orange-color\">60 \u2013 Em rela\u00e7\u00e3o \u00e0 acidez e a basicidade dos compostos..<\/span><\/em><\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra A: Negativo \u2013 metais de transi\u00e7\u00e3o t\u00eam subn\u00edveis \u2013 que s\u00e3o capazes de receber el\u00e9trons. Possuem comportamentos mais \u00e1cidos.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra B: Gabarito. Pegadinha: \u00e1cido fosforoso tem f\u00f3rmula molecular H3 PO3 \u2013 quando olhamos para a f\u00f3rmula molecular do \u00e1cido fosforoso, vemos 3 hidrog\u00eanios ioniz\u00e1veis. O \u00e1cido fosforoso \u00e9 \u00e1cido tripr\u00f3trico, porque ele tem 3 hidrog\u00eanios e somente 2 (dos 3) s\u00e3o ioniz\u00e1veis, o que \u00e9 uma exce\u00e7\u00e3o.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra C: Fl\u00faor \u00e9 mais eletronegativo, ent\u00e3o, pelo efeito indutivo, ele puxa mais el\u00e9trons pra si e o hidrog\u00eanio fica mais dispon\u00edvel, mais \u00e1cido.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra D: Voc\u00ea deve comparar a raz\u00e3o massa\/carga entre o cobre o ferro. O ferro \u00e9 maior, logo, eu tenho maior car\u00e1ter \u00e1cido, porque em alguns casos o ferro vai se ligar t\u00e3o fortemente ao polo negativo da \u00e1gua neste processo de hidrata\u00e7\u00e3o, puxando tanto el\u00e9trons do oxig\u00eanio pra si, por conta da sua carga, que o oxig\u00eanio da \u00e1gua vai acabar perdendo o hidrog\u00eanio na forma de H+.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Letra E: O fenol \u00e9 anel arom\u00e1tico com hidroxila na parte de cima. Se o fenol perder o hidrog\u00eanio ligado ao oxig\u00eanio da hidroxila, esta carga negativa que fica em cima do oxig\u00eanio pode sofrer resson\u00e2ncia com o anel arom\u00e1tico. E esta resson\u00e2ncia estabiliza a base conjugada. Quando estabilizo a base conjugada eu tenho um \u00e1cido mais forte.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>GABARITO: B<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">Esperamos que tenham tido um bom desempenho!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Ol\u00e1, pessoal. Tudo bem? Neste artigo faremos uma breve corre\u00e7\u00e3o da prova de Qu\u00edmica aplicada para o cargo de Papiloscopista da Pol\u00edcia Civil do Par\u00e1. Vale ressaltar que essa corre\u00e7\u00e3o \u00e9 EXTRAOFICIAL, sendo necess\u00e1rio aguardar o gabarito preliminar da banca para confirmar o seu desempenho. Vamos l\u00e1? Prova de Qu\u00edmica- Cargo: PAPILOSCOPISTA 56 \u2013 A [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":786424,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"post_tipo":"article","footnotes":""},"categories":[1988],"tags":[],"tax_estado":[219977],"class_list":["post-787103","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-policia","tax_estado-pa"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v28.0 (Yoast SEO v28.0) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Gabarito Extraoficial PC PA - Qu\u00edmica (Papiloscopista)<\/title>\n<meta name=\"description\" content=\"Confira aqui a corre\u00e7\u00e3o extraoficial da prova de Qu\u00edmica, cargo de Papiloscopista, da Pol\u00eccia Civil do Par\u00e1.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-pc-pa-quimica\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Gabarito Extraoficial PC PA - Qu\u00edmica (Papiloscopista)\" \/>\n<meta property=\"og:description\" content=\"Confira aqui a corre\u00e7\u00e3o extraoficial da prova de Qu\u00edmica, cargo de Papiloscopista, da Pol\u00eccia Civil do Par\u00e1.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-pc-pa-quimica\/\" \/>\n<meta property=\"og:site_name\" content=\"Estrat\u00e9gia Concursos\" \/>\n<meta property=\"article:author\" content=\"https:\/\/www.facebook.com\/EstrategiaConcursos\" \/>\n<meta property=\"article:published_time\" content=\"2021-07-05T15:57:33+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2021-07-05T15:59:48+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/07\/04182023\/concurso-pc-pa-2.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1200\" \/>\n\t<meta property=\"og:image:height\" content=\"628\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Coordena\u00e7\u00e3o\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@EstratConcursos\" \/>\n<meta name=\"twitter:site\" content=\"@EstratConcursos\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Coordena\u00e7\u00e3o\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"4 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\\\/\\\/schema.org\",\"@graph\":[{\"@type\":\"NewsArticle\",\"@id\":\"https:\\\/\\\/www.estrategiaconcursos.com.br\\\/blog\\\/gabarito-extraoficial-pc-pa-quimica\\\/#article\",\"isPartOf\":{\"@id\":\"https:\\\/\\\/www.estrategiaconcursos.com.br\\\/blog\\\/gabarito-extraoficial-pc-pa-quimica\\\/\"},\"author\":{\"name\":\"Coordena\u00e7\u00e3o\",\"@id\":\"https:\\\/\\\/www.estrategiaconcursos.com.br\\\/blog\\\/#\\\/schema\\\/person\\\/b4a388c97673c5f483d72185668afa1f\"},\"headline\":\"Gabarito Extraoficial PC PA &#8211; 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