{"id":787095,"date":"2021-07-05T12:44:05","date_gmt":"2021-07-05T15:44:05","guid":{"rendered":"https:\/\/www.estrategiaconcursos.com.br\/blog\/?p=787095"},"modified":"2021-07-05T12:44:07","modified_gmt":"2021-07-05T15:44:07","slug":"gabarito-extraoficial-pc-pa-fisica","status":"publish","type":"post","link":"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-pc-pa-fisica\/","title":{"rendered":"Gabarito Extraoficial PC PA &#8211; F\u00edsica (Papiloscopista)"},"content":{"rendered":"\n<p>Ol\u00e1, pessoal. Tudo bem?<\/p>\n\n\n\n<p>Neste artigo faremos uma breve corre\u00e7\u00e3o da prova de<strong> F\u00edsica <\/strong>aplicada para o cargo de <strong>Papiloscopista<\/strong> da Pol\u00edcia Civil do Par\u00e1. Vale ressaltar que essa corre\u00e7\u00e3o \u00e9 EXTRAOFICIAL, sendo necess\u00e1rio aguardar o gabarito preliminar da banca para confirmar o seu desempenho.<\/p>\n\n\n\n<p><em>Vamos l\u00e1?<\/em><\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-prova-de-f-sica-cargo-papiloscopista\">Prova de F\u00edsica &#8211; Cargo: PAPILOSCOPISTA<\/h2>\n\n\n\n<p><em><strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">51 \u2013 Considere o circuito el\u00e9trico da figura&#8230;<\/span><\/strong><\/em><\/p>\n\n\n\n<p>Letra A: Falso \u2013 s\u00f3 teria 3R se estivesse associado em s\u00e9rie.<\/p>\n\n\n\n<p>Letra B: N\u00e3o, porque as correntes el\u00e9tricas que passam por elas s\u00e3o distintas \u2013 ir\u00e1 apresentar o mesmo brilho quando tem a mesma corrente el\u00e9trica e a mesma resist\u00eancia.<\/p>\n\n\n\n<p>Letra C: T\u00e1 certo \u2013 porque a corrente el\u00e9trica que passa por L2 \u00e9 metade da corrente que passa por L1.<\/p>\n\n\n\n<p>Letra D: N\u00e3o \u2013 quando voc\u00ea tira L2 do bocal vai deixar de ter uma associa\u00e7\u00e3o em paralelo entre L2 e L3.<\/p>\n\n\n\n<p>Letra E: Errado \u2013 L1 n\u00e3o est\u00e1 associado em paralelo a L3.<\/p>\n\n\n\n<p><strong>Gabarito: C<\/strong><\/p>\n\n\n\n<p><em><strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">52 \u2013 Em rela\u00e7\u00e3o \u00e0s lupas, assinale a alternativa correta:<\/span><\/strong><\/em><\/p>\n\n\n\n<p>Letra A: Errado \u2013 Lente convergente (e n\u00e3o divergente).<\/p>\n\n\n\n<p>Letra B: Objeto tem que estar entre o foco e a lente.<\/p>\n\n\n\n<p>Letra C: N\u00e3o \u2013 quando est\u00e1 do mesmo lado \u00e9 virtual e direita.<\/p>\n\n\n\n<p>Letra D: Se fizer o c\u00e1lculo vai dar 5cm \u2013 N\u00e3o \u00e9 correto.<\/p>\n\n\n\n<p>Letra E: Gabarito da quest\u00e3o.<\/p>\n\n\n\n<p><strong>Gabarito: E<\/strong><\/p>\n\n\n\n<p><strong><em><span class=\"has-inline-color has-luminous-vivid-orange-color\">53 \u2013 Considerando uma part\u00edcula de carga&#8230;<\/span><\/em><\/strong><\/p>\n\n\n\n<p>Letra A: Repuls\u00e3o ocorre quando iguais.<\/p>\n\n\n\n<p>Letra B: N\u00e3o \u2013 porque no ponto m\u00e9dio voc\u00ea vai ter um campo el\u00e9trico de repuls\u00e3o e atra\u00e7\u00e3o na negativa.<\/p>\n\n\n\n<p>Letra C: Sim, potencial \u00e9 a soma \u2013 leva em considera\u00e7\u00e3o o sinal da carga.<\/p>\n\n\n\n<p>Letra D: N\u00e3o \u2013 vai quadriplicar.<\/p>\n\n\n\n<p>Letra E: N\u00e3o \u2013 vai diminuir a for\u00e7a.<\/p>\n\n\n\n<p><strong>Gabarito: C<\/strong><\/p>\n\n\n\n<p><em><strong><span class=\"has-inline-color has-luminous-vivid-orange-color\">54 \u2013 Um bloco de massa m=200 g &#8230;.<\/span><\/strong><\/em><\/p>\n\n\n\n<p>Letra A: C\u00e1lculo da f\u00f3rmula n\u00e3o vai chegar no resultado.<\/p>\n\n\n\n<p>Letra B: Falso, foi dito que \u00e9 2,5.<\/p>\n\n\n\n<p>Letra C: Falso, foi dito que \u00e9 2,5.<\/p>\n\n\n\n<p>Letra D: Certo \u2013 acelera\u00e7\u00e3o m\u00e1xima.<\/p>\n\n\n\n<p>Letra E: Errado \u2013 fala da energia mec\u00e2nica \u2013 vai dar 0,025 e n\u00e3o 2,5.<\/p>\n\n\n\n<p><strong>Gabarito: D<\/strong><\/p>\n\n\n\n<p><strong><em>55 &#8211; Uma das raias do espectro vis\u00edvel&#8230;<\/em><\/strong><\/p>\n\n\n\n<p>Gabarito letra B \u2013 Esta quest\u00e3o precisava fazer c\u00e1lculo e\/ou usar o \u00e1tomo de Bohr.<\/p>\n\n\n\n<hr class=\"wp-block-separator\"\/>\n\n\n\n<p>Esperamos que tenham tido um bom desempenho!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Ol\u00e1, pessoal. Tudo bem? Neste artigo faremos uma breve corre\u00e7\u00e3o da prova de F\u00edsica aplicada para o cargo de Papiloscopista da Pol\u00edcia Civil do Par\u00e1. Vale ressaltar que essa corre\u00e7\u00e3o \u00e9 EXTRAOFICIAL, sendo necess\u00e1rio aguardar o gabarito preliminar da banca para confirmar o seu desempenho. Vamos l\u00e1? Prova de F\u00edsica &#8211; Cargo: PAPILOSCOPISTA 51 \u2013 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":786424,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"post_tipo":"article","footnotes":""},"categories":[1988],"tags":[],"tax_estado":[219977],"class_list":["post-787095","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-policia","tax_estado-pa"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.2 (Yoast SEO v27.2) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Gabarito Extraoficial PC PA - F\u00edsica (Papiloscopista)<\/title>\n<meta name=\"description\" content=\"Confira aqui a corre\u00e7\u00e3o extraoficial da prova de F\u00edsica, cargo de Papiloscopista, da Pol\u00eccia Civil do Par\u00e1.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-pc-pa-fisica\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Gabarito Extraoficial PC PA - F\u00edsica (Papiloscopista)\" \/>\n<meta property=\"og:description\" content=\"Confira aqui a corre\u00e7\u00e3o extraoficial da prova de F\u00edsica, cargo de Papiloscopista, da Pol\u00eccia Civil do Par\u00e1.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-pc-pa-fisica\/\" \/>\n<meta property=\"og:site_name\" content=\"Estrat\u00e9gia Concursos\" \/>\n<meta property=\"article:author\" content=\"https:\/\/www.facebook.com\/EstrategiaConcursos\" \/>\n<meta property=\"article:published_time\" content=\"2021-07-05T15:44:05+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2021-07-05T15:44:07+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/07\/04182023\/concurso-pc-pa-2.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1200\" \/>\n\t<meta property=\"og:image:height\" content=\"628\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"Coordena\u00e7\u00e3o\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@EstratConcursos\" \/>\n<meta name=\"twitter:site\" content=\"@EstratConcursos\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Coordena\u00e7\u00e3o\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"NewsArticle\",\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-pc-pa-fisica\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/gabarito-extraoficial-pc-pa-fisica\/\"},\"author\":{\"name\":\"Coordena\u00e7\u00e3o\",\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/#\/schema\/person\/b4a388c97673c5f483d72185668afa1f\"},\"headline\":\"Gabarito Extraoficial PC PA &#8211; 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