{"id":77283,"date":"2017-06-12T01:26:28","date_gmt":"2017-06-12T04:26:28","guid":{"rendered":"https:\/\/www.estrategiaconcursos.com.br\/blog\/?p=77283"},"modified":"2018-09-19T15:20:00","modified_gmt":"2018-09-19T18:20:00","slug":"media-aritmetica","status":"publish","type":"post","link":"https:\/\/www.estrategiaconcursos.com.br\/blog\/media-aritmetica\/","title":{"rendered":"M\u00e9dia Aritm\u00e9tica &#8211; voc\u00ea conhece as 3 formas de c\u00e1lculo?"},"content":{"rendered":"<h2 style=\"text-align: justify;\">M\u00e9dia Aritm\u00e9tica &#8211; revisando as 3 formas de c\u00e1lculo<\/h2>\n<p style=\"text-align: justify;\">Fala pessoal, tudo bem? Como voc\u00eas sabem, M\u00e9dia Aritm\u00e9tica \u00e9 um assunto presente em uma grande variedade de concursos. O examinador pode te fornecer os dados de TR\u00caS formas diferentes, e cada uma delas ter\u00e1 um c\u00e1lculo diferente:<\/p>\n<p style=\"text-align: justify;\">1) dados em rol (lista de n\u00fameros);<\/p>\n<p style=\"text-align: justify;\">2) dados em uma tabela de frequ\u00eancias;<\/p>\n<p style=\"text-align: justify;\">3) dados em uma tabela com intervalos de classes.<\/p>\n<p style=\"text-align: justify;\">Para te ajudar a relembrar, vou deixar neste artigo 3 quest\u00f5es resolvidas, uma sobre cada tipo. Vamos l\u00e1?<\/p>\n<h2 style=\"text-align: justify;\"><\/h2>\n<h2 style=\"text-align: justify;\">M\u00e9dia aritm\u00e9tica para dados em rol (lista de dados)<\/h2>\n<p style=\"text-align: justify;\"><strong>1. VUNESP \u2013 SPTRANS \u2013 2012)<\/strong> O\u00a0n\u00famero de acidentes com motos, em determinada cidade, no decorrer de 5 dias, foi igual a:<\/p>\n<p style=\"text-align: center;\">6, 3, 4, 2, ?<\/p>\n<p style=\"text-align: justify;\">Na m\u00e9dia, o n\u00famero de acidentes por dia foi 4,4. Se tivesse ocorrido mais um acidente no \u00faltimo dia (?), a m\u00e9dia di\u00e1ria desses 5 dias teria sido de:<\/p>\n<p style=\"text-align: justify;\">(A) 4,5.<\/p>\n<p style=\"text-align: justify;\">(B) 4,6.<\/p>\n<p style=\"text-align: justify;\">(C) 4,7.<\/p>\n<p style=\"text-align: justify;\">(D) 4,8.<\/p>\n<p style=\"text-align: justify;\">(E) 4,9.<\/p>\n<p style=\"text-align: justify;\"><strong>RESOLU\u00c7\u00c3O:<\/strong><\/p>\n<p style=\"text-align: justify;\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Se a m\u00e9dia de acidentes ao longo dos 5 dias foi de 4,4, podemos escrever:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-77317\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12092451\/media11.png\" alt=\"\" width=\"286\" height=\"402\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12092451\/media11.png 286w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12092451\/media11.png 213w\" sizes=\"auto, (max-width: 286px) 100vw, 286px\" \/><\/p>\n<p style=\"text-align: justify;\">Portanto, no \u00faltimo dia\u00a0ocorreram 7 acidentes. Se tivesse ocorrido mais 1, ou seja, um total de 8 acidentes, a m\u00e9dia seria:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-77290\" style=\"text-align: justify;\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12012122\/m%C3%A9dia2.png\" alt=\"\" width=\"272\" height=\"71\" \/><\/p>\n<p>&nbsp;<\/p>\n<p style=\"text-align: justify;\"><strong>FORMA MAIS R\u00c1PIDA:\u00a0<\/strong>voc\u00ea poderia resolver essa quest\u00e3o rapidamente. Veja que houve o aumento de 1 acidente. Como, no c\u00e1lculo da m\u00e9dia, \u00e9 preciso dividir por 5, ent\u00e3o o aumento na m\u00e9dia ser\u00e1 de 1\/5, ou seja, de 0,2. Assim, a nova m\u00e9dia ser\u00e1:<\/p>\n<p style=\"text-align: center;\">4,4 + 0,2 = 4,6<\/p>\n<p style=\"text-align: justify;\"><strong>Resposta: B<\/strong><\/p>\n<h2 style=\"text-align: justify;\">M\u00e9dia aritm\u00e9tica para tabela de frequ\u00eancias<\/h2>\n<p style=\"text-align: justify;\"><strong>2. VUNESP \u2013 TJM\/SP \u2013 2017)<\/strong> A tabela apresenta o n\u00famero de acertos dos 600 candidatos que realizaram a prova da segunda fase de um concurso, que continha 5 quest\u00f5es de m\u00faltipla escolha.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-77284\" style=\"text-align: justify;\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12010236\/media-aritmetica-tabela.png\" alt=\"media aritmetica\" width=\"268\" height=\"134\" \/><\/p>\n<p style=\"text-align: justify;\">A m\u00e9dia de acertos por prova foi de<\/p>\n<p style=\"text-align: justify;\">(A) 3,57.<\/p>\n<p style=\"text-align: justify;\">(B) 3,43.<\/p>\n<p style=\"text-align: justify;\">(C) 3,32.<\/p>\n<p style=\"text-align: justify;\">(D) 3,25.<\/p>\n<p style=\"text-align: justify;\">(E) 3,19.<\/p>\n<p style=\"text-align: justify;\"><b>RESOLU\u00c7\u00c3O<\/b><\/p>\n<h2 style=\"text-align: justify;\">M\u00e9dia aritm\u00e9tica para tabela com intervalos de classes<\/h2>\n<p style=\"text-align: justify;\"><strong>3. IDECAN \u2013 BOMBEIROS\/DF \u2013 2017) <\/strong>A m\u00e9dia aritm\u00e9tica da distribui\u00e7\u00e3o de frequ\u00eancias a seguir \u00e9:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-77285\" style=\"text-align: justify;\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12010545\/media-aritmetica-intervalos.png\" alt=\"media aritmetica\" width=\"174\" height=\"139\" \/><\/p>\n<p style=\"text-align: justify;\">A) 4,9.<\/p>\n<p style=\"text-align: justify;\">B) 5,2.<\/p>\n<p style=\"text-align: justify;\">C) 5,3.<\/p>\n<p style=\"text-align: justify;\">D) 5,5.<\/p>\n<p style=\"text-align: justify;\"><b>RESOLU\u00c7\u00c3O:<\/b><\/p>\n<p style=\"text-align: justify;\">Aqui temos uma tabela com intervalos de classes. A f\u00f3rmula de c\u00e1lculo da m\u00e9dia \u00e9:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-77286\" style=\"text-align: justify;\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12010744\/media-aritmetica-formula.png\" alt=\"media aritmetica formula\" width=\"240\" height=\"121\" \/><\/p>\n<p style=\"text-align: justify;\">A aplica\u00e7\u00e3o desta f\u00f3rmula \u00e9 bem simples. Basta:<\/p>\n<p style=\"text-align: justify;\"><strong>1) calcular\u00a0os pontos m\u00e9dios de cada intervalo.<\/strong> Para isto basta somar os extremos de cada intervalo e dividir por 2. Por exemplo, o ponto m\u00e9dio do intervalo 0&#8211;2 \u00e9 calculado assim: \u00a0(0 + 2) \/ 2 = 1. Fazendo isso para os demais intervalos, temos:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-77287\" style=\"text-align: justify;\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12011207\/tabela1.png\" alt=\"\" width=\"409\" height=\"126\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12011207\/tabela1.png 409w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12011207\/tabela1.png 300w\" sizes=\"auto, (max-width: 409px) 100vw, 409px\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>2) multiplicar cada ponto m\u00e9dio pela respectiva frequ\u00eancia, obtendo os termos PMi . fi:\u00a0<\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-full wp-image-77288\" style=\"text-align: justify;\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12011317\/tabela2.png\" alt=\"\" width=\"568\" height=\"127\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12011317\/tabela2.png 568w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2017\/06\/12011317\/tabela2.png 300w\" sizes=\"auto, (max-width: 568px) 100vw, 568px\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>3) somar os termos da coluna PMi.fi, obtendo o numerador da f\u00f3rmula da m\u00e9dia (somat\u00f3rio de PMi.fi):<\/strong><\/p>\n<p style=\"text-align: justify;\">Em nosso exemplo, a soma da coluna PMi.fi \u00e9 igual a 520.<\/p>\n<p style=\"text-align: justify;\"><strong>4) somar os termos da coluna das frequ\u00eancias, obtendo o denominador da f\u00f3rmula da m\u00e9dia (somat\u00f3rio de fi):<\/strong><\/p>\n<p style=\"text-align: justify;\">Em nosso exemplo, a soma da coluna das frequ\u00eancias \u00e9 100.<\/p>\n<p style=\"text-align: justify;\"><strong>5) dividir a soma da coluna PMi.fi pela soma da coluna das frequ\u00eancias, obtendo a m\u00e9dia:<\/strong><\/p>\n<p style=\"text-align: justify;\">Portanto, m\u00e9dia = 520 \/ 100 = 5,2.<\/p>\n<p style=\"text-align: justify;\"><b>Resposta: B<\/b><\/p>\n<p style=\"text-align: justify;\">Espero que voc\u00ea tenha conseguido relembrar cada um dos c\u00e1lculos!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>M\u00e9dia Aritm\u00e9tica &#8211; revisando as 3 formas de c\u00e1lculo Fala pessoal, tudo bem? Como voc\u00eas sabem, M\u00e9dia Aritm\u00e9tica \u00e9 um assunto presente em uma grande variedade de concursos. O examinador pode te fornecer os dados de TR\u00caS formas diferentes, e cada uma delas ter\u00e1 um c\u00e1lculo diferente: 1) dados em rol (lista de n\u00fameros); 2) [&hellip;]<\/p>\n","protected":false},"author":741,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"post_tipo":"article","footnotes":""},"categories":[1],"tags":[],"tax_estado":[],"class_list":["post-77283","post","type-post","status-publish","format-standard","hentry","category-cursos-e-concursos"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.2 (Yoast SEO v27.2) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>M\u00e9dia Aritm\u00e9tica - conhe\u00e7a as tr\u00eas formas de c\u00e1lculo<\/title>\n<meta name=\"description\" content=\"Veja neste artigo as tr\u00eas formas de c\u00e1lculo da m\u00e9dia aritm\u00e9tica, assunto bastante exigido nos concursos p\u00fablicos!\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/media-aritmetica\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"M\u00e9dia Aritm\u00e9tica - voc\u00ea conhece as 3 formas de c\u00e1lculo?\" \/>\n<meta property=\"og:description\" content=\"Veja neste artigo as tr\u00eas formas de c\u00e1lculo da m\u00e9dia aritm\u00e9tica, assunto bastante exigido nos concursos p\u00fablicos!\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/media-aritmetica\/\" \/>\n<meta property=\"og:site_name\" content=\"Estrat\u00e9gia Concursos\" \/>\n<meta property=\"article:published_time\" content=\"2017-06-12T04:26:28+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2018-09-19T18:20:00+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/wp-content\/uploads\/2017\/06\/media11.png\" \/>\n<meta name=\"author\" content=\"Brunno Lima\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@EstratConcursos\" \/>\n<meta name=\"twitter:site\" content=\"@EstratConcursos\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Brunno Lima\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"NewsArticle\",\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/media-aritmetica\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/media-aritmetica\/\"},\"author\":{\"name\":\"Brunno Lima\",\"@id\":\"https:\/\/www.estrategiaconcursos.com.br\/blog\/#\/schema\/person\/2865ec132c3404c9912015dd7a24eb1e\"},\"headline\":\"M\u00e9dia Aritm\u00e9tica &#8211; 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