{"id":651138,"date":"2024-08-01T10:47:00","date_gmt":"2024-08-01T13:47:00","guid":{"rendered":"https:\/\/www.estrategiaconcursos.com.br\/blog\/?p=651138"},"modified":"2024-08-08T11:38:48","modified_gmt":"2024-08-08T14:38:48","slug":"fisica-para-a-prf","status":"publish","type":"post","link":"https:\/\/www.estrategiaconcursos.com.br\/blog\/fisica-para-a-prf\/","title":{"rendered":"F\u00edsica para a PRF: F\u00f3rmulas de F\u00edsica para gabaritar na prova!"},"content":{"rendered":"\n<p>Ol\u00e1, Estrategista. Tudo joia?<\/p>\n\n\n\n<p>Hoje iremos falar sobre um assunto que \u00e9 o pesadelo de muitos candidatos que prestam o concurso Pol\u00edcia Rodovi\u00e1ria Federal: F\u00cdSICA para a PRF. Ali\u00e1s, quando o assunto \u00e9 exatas, n\u00fameros, muitos sentem at\u00e9 calafrios.<\/p>\n\n\n\n<p>Para quem n\u00e3o me conhece, me chamo <a href=\"https:\/\/www.estrategiaconcursos.com.br\/professor\/leandro-ricardo-machado-da-silveira-4226\/\" target=\"_blank\" rel=\"noreferrer noopener\">Leandro, sou Auditor-Fiscal da SEFAZ-SC<\/a>, aprovado no \u00faltimo concurso na 24\u00ba posi\u00e7\u00e3o. Para quem quiser trocar uma ideia ou tirar uma d\u00favida, sinta-se \u00e0 vontade para me chamar nas redes sociais.<\/p>\n\n\n\n<p>Mas tenhamos calma, tamb\u00e9m n\u00e3o \u00e9 esse bicho de sete cabe\u00e7as. Para que tenhamos um bom \u00edndice de <strong>acertos em f\u00edsica<\/strong> \u00e9 preciso que saibamos<strong> organizar as informa\u00e7\u00f5es<\/strong> que o enunciado da quest\u00e3o nos passa e aplicarmos essas informa\u00e7\u00f5es nas f\u00f3rmulas que temos dispon\u00edveis.<\/p>\n\n\n\n<p>Geralmente, quest\u00f5es f\u00e1ceis necessitam da aplica\u00e7\u00e3o de<strong> 1 f\u00f3rmula apenas<\/strong>; justamente por isso, s\u00e3o consideradas f\u00e1ceis. J\u00e1 quest\u00f5es mais complexas necessitam de 2 ou mais f\u00f3rmulas. Ou seja, uma f\u00f3rmula acaba se tornando pr\u00e9-requisito para outra.<\/p>\n\n\n\n<div class=\"wp-block-yoast-seo-table-of-contents yoast-table-of-contents\"><ul><li><a href=\"#h-dicas-de-formulas-fisicas-para-prf\" data-level=\"2\">Dicas de f\u00f3rmulas f\u00edsicas para PRF<\/a><\/li><li><a href=\"#h-movimento-retilineo-uniforme-mru\" data-level=\"2\">Movimento Retil\u00edneo Uniforme \u2013 MRU<\/a><\/li><li><a href=\"#h-movimento-retilineo-uniformemente-variado-mruv\" data-level=\"2\">Movimento Retil\u00edneo Uniformemente Variado \u2013 MRUV<\/a><\/li><li><a href=\"#h-observacao-sobre-lancamento-obliquo\" data-level=\"2\">OBSERVA\u00c7\u00c3O SOBRE LAN\u00c7AMENTO OBL\u00cdQUO<\/a><\/li><li><a href=\"#h-velocidade-vetorial\" data-level=\"2\">Velocidade vetorial<\/a><\/li><li><a href=\"#h-aceleracao-centripeta\" data-level=\"2\">Acelera\u00e7\u00e3o Centr\u00edpeta<\/a><\/li><li><a href=\"#h-fisica-para-a-prf-transmissao-de-movimentos-circulares\" data-level=\"2\">F\u00edsica para a PRF: Transmiss\u00e3o de movimentos circulares<\/a><ul><li><a href=\"#h-por-contato\" data-level=\"3\">Por contato<\/a><\/li><li><a href=\"#h-transmissao-por-correia\" data-level=\"3\">Transmiss\u00e3o por correia<\/a><\/li><li><a href=\"#h-transmissao-por-eixo\" data-level=\"3\">Transmiss\u00e3o por eixo<\/a><\/li><\/ul><\/li><li><a href=\"#h-leis-de-newton\" data-level=\"2\">Leis de Newton<\/a><ul><li><a href=\"#h-conceito-de-forca\" data-level=\"3\">Conceito de For\u00e7a<\/a><\/li><\/ul><\/li><li><a href=\"#h-trabalho\" data-level=\"2\">Trabalho<\/a><ul><li><a href=\"#h-trabalho-da-forca-elastica\" data-level=\"3\">Trabalho da For\u00e7a El\u00e1stica<\/a><\/li><\/ul><\/li><li><a href=\"#h-energia-cinetica-e-potencial\" data-level=\"2\">Energia Cin\u00e9tica e Potencial<\/a><ul><li><a href=\"#h-teoria-da-energia-cinetica\" data-level=\"3\">Teoria da Energia Cin\u00e9tica<\/a><\/li><li><a href=\"#h-conservacao-da-energia\" data-level=\"3\">Conserva\u00e7\u00e3o da Energia<\/a><\/li><\/ul><\/li><li><a href=\"#h-potencia\" data-level=\"2\">Pot\u00eancia<\/a><\/li><li><a href=\"#h-impulso\" data-level=\"2\">Impulso<\/a><\/li><li><a href=\"#h-quantidade-de-movimento\" data-level=\"2\">Quantidade de Movimento<\/a><ul><li><a href=\"#h-teorema-do-impulso\" data-level=\"3\">Teorema do Impulso<\/a><\/li><\/ul><\/li><li><a href=\"#h-principais-formulas-de-fisica-para-a-prf\" data-level=\"2\">Principais f\u00f3rmulas de f\u00edsica para a PRF<\/a><\/li><li><a href=\"#h-cursos-e-assinaturas\" data-level=\"2\">Cursos e Assinaturas<\/a><\/li><\/ul><\/div>\n\n\n\n<div class=\"container\" id=\"boxes\">\n  <div class=\"row\"> \n\n    <div class=\"col-sm\">\n      <div class=\"banner-federais\" id=\"box-assinatura\">\n        <h2 class=\"titulo-assinatura\">Estude F\u00edsica para a PRF<\/h2>\n        <p class=\"subtitulo-assinatura\">Ao final do curso receba um certificado!<\/p>\n        <div class=\"box-botao\">\n          <a class=\"btn-assinatura\" target=\"_blank\" href=\"https:\/\/www.estrategiaconcursos.com.br\/curso\/prf-policial-fisica\/?utm_source=blog&#038;utm_medium=banner&#038;utm_campaign=prf-fisica\" role=\"button\" rel=\"noopener noreferrer\">INICIAR AGORA<\/a>\n        <\/div>\n      <\/div>\n     \n\n  <\/div>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-dicas-de-formulas-fisicas-para-prf\">Dicas de f\u00f3rmulas f\u00edsicas para PRF<\/h2>\n\n\n\n<p>Por falarmos em f\u00f3rmulas, permita-me dar um macete aos iniciantes e \u00e0queles que possuem bastante dificuldades nessa mat\u00e9ria: uma f\u00f3rmula \u00e9 nada mais nada menos que um conjunto de vari\u00e1veis. Portanto, s\u00f3 faz sentido utilizarmos aquela f\u00f3rmula se tivermos informa\u00e7\u00e3o de todas as vari\u00e1veis menos uma (n-1).<\/p>\n\n\n\n<p><strong>Exemplo: <\/strong>Imaginemos que o enunciado da quest\u00e3o forne\u00e7a 3 dados. Se uma f\u00f3rmula espec\u00edfica contiver 4 vari\u00e1veis, sendo que dessas 4, 3 s\u00e3o poss\u00edveis de se extrair do enunciado, <strong>BINGO<\/strong>. \u00c9 poss\u00edvel calcular a 4\u00aa vari\u00e1vel.<\/p>\n\n\n\n<p>Por outro lado, se das 4 vari\u00e1veis da equa\u00e7\u00e3o, apenas 2 forem poss\u00edveis de se extrair do enunciado, ser\u00e1 preciso utilizar-se de outra f\u00f3rmula para o c\u00e1lculo da 3\u00aa vari\u00e1vel e, s\u00f3 assim, <strong>voltar \u00e0 primeira f\u00f3rmula e calcular a 4\u00aa vari\u00e1vel<\/strong>.<\/p>\n\n\n\n<p>Indiscutivelmente ent\u00e3o, antes de mais nada, precisaremos saber quais s\u00e3o as principais f\u00f3rmulas de f\u00edsica para PRF, se quisermos ter um bom percentual de assertividade, certo?<\/p>\n\n\n\n<p>Vamos l\u00e1.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-movimento-retilineo-uniforme-mru\">Movimento Retil\u00edneo Uniforme \u2013 MRU<\/h2>\n\n\n\n<p>O Movimento Retil\u00edneo e Uniforme \u2013 MRU \u00e9 aquele movimento cuja trajet\u00f3ria \u00e9 retil\u00ednea e a velocidade se mant\u00e9m constante durante todo o movimento. Ou seja, n\u00e3o temos acelera\u00e7\u00e3o.<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"213\" height=\"79\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103111\/image-140.png\" alt=\"MRU movimento ritil\u00edneo uniforme - f\u00f3rmula de f\u00edsica para a PRF\" class=\"wp-image-651143\"\/><figcaption class=\"wp-element-caption\">MRU<\/figcaption><\/figure>\n\n\n\n<p>Nada mais nada menos que varia\u00e7\u00e3o da dist\u00e2ncia percorrida (\u2206S) dividido pelo intervalo de tempo gasto para percorrer essa dist\u00e2ncia.<\/p>\n\n\n\n<p>Se:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"163\" height=\"84\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103138\/image-141.png\" alt=\"F\u00f3rmula da dist\u00e2ncia sobre o intervalo de tempo\" class=\"wp-image-651145\"\/><\/figure>\n\n\n\n<p>Ent\u00e3o:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"187\" height=\"51\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103148\/image-142.png\" alt=\"Dist\u00e2ncia inicial mais velocidade vezes tempo\" class=\"wp-image-651146\"\/><\/figure>\n\n\n\n<p>Dist\u00e2ncia final \u00e9 igual a dist\u00e2ncia inicial (geralmente 0) mais velocidade x tempo.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-movimento-retilineo-uniformemente-variado-mruv\">Movimento Retil\u00edneo Uniformemente Variado \u2013 MRUV<\/h2>\n\n\n\n<p>O MRUV \u00e9 o movimento que possui trajet\u00f3ria retil\u00ednea e acelera\u00e7\u00e3o constante. Ou seja, a velocidade varia, seja para mais ou para menos.<\/p>\n\n\n\n<p>Ali\u00e1s, \u00e9 poss\u00edvel ter velocidade negativa? Imagine por exemplo que um proj\u00e9til seja atirado para cima. A partir do momento que a bala \u00e9 lan\u00e7ada verticalmente, a \u00fanica acelera\u00e7\u00e3o que estar\u00e1 atuando sobre o proj\u00e9til \u00e9 a da gravidade, freando o disparo (durante a subida).<\/p>\n\n\n\n<p>Portanto, ao realizarmos o c\u00e1lculo e chegarmos a <strong>uma velocidade final negativa<\/strong>, n\u00e3o se assuste. O que velocidade negativa nos mostra \u00e9 que o sentido final do proj\u00e9til est\u00e1 oposto ao sentido inicial. Nesse exemplo, a bala j\u00e1 teria subido at\u00e9 o limite da altura do disparo e estaria caindo de volta \u00e0 terra.<\/p>\n\n\n\n<p>Se a acelera\u00e7\u00e3o for constante, a f\u00f3rmula \u00e9 a seguinte:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"209\" height=\"79\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103159\/image-143.png\" alt=\"\" class=\"wp-image-651148\"\/><\/figure>\n\n\n\n<p>Se:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"142\" height=\"77\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103209\/image-144.png\" alt=\"\" class=\"wp-image-651150\"\/><\/figure>\n\n\n\n<p>Ent\u00e3o:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"187\" height=\"51\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103219\/image-145.png\" alt=\"\" class=\"wp-image-651151\"\/><\/figure>\n\n\n\n<p>Outra f\u00f3rmula a se anotar:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"240\" height=\"75\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103238\/image-146.png\" alt=\"\" class=\"wp-image-651152\"\/><\/figure>\n\n\n\n<p>Terceira f\u00f3rmula a se saber:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"227\" height=\"63\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103249\/image-147.png\" alt=\"\" class=\"wp-image-651153\"\/><\/figure>\n\n\n\n<p><strong>Exemplo<\/strong>: imagine que um proj\u00e9til seja disparado verticalmente com velocidade inicial = 10 m\/s. Pergunta-se: qual o tempo para que o proj\u00e9til retorne ao solo?<\/p>\n\n\n\n<p>Primeiramente, anota-se: a acelera\u00e7\u00e3o \u00e9 a da gravidade = 10 m\/s\u00b2.<\/p>\n\n\n\n<p>A maneira mais simples de se resolver esse exerc\u00edcio \u00e9 dividir em <strong>2 percursos<\/strong>: o da subida (onde a acelera\u00e7\u00e3o estar\u00e1 freando a bala) e o da descida (onde a acelera\u00e7\u00e3o estar\u00e1 acelerando o corpo).<\/p>\n\n\n\n<p>Subida: a velocidade final \u00e9 0, pois o projeto precisa parar de subir para poder cair e a acelera\u00e7\u00e3o \u00e9 negativa, pois est\u00e1 freando. Logo:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"205\" height=\"113\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103303\/image-148.png\" alt=\"\" class=\"wp-image-651154\"\/><\/figure>\n\n\n\n<p>Com isso, vamos calcular a dist\u00e2ncia percorrida na subida (o sinal da acelera\u00e7\u00e3o \u00e9 muito importante):<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"402\" height=\"102\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103326\/image-149.png\" alt=\"\" class=\"wp-image-651156\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103326\/image-149.png 402w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103326\/image-149-300x76.png 300w\" sizes=\"auto, (max-width: 402px) 100vw, 402px\" \/><\/figure>\n\n\n\n<p>Descida: a velocidade inicial \u00e9 0 e a acelera\u00e7\u00e3o \u00e9 positiva:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"201\" height=\"55\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103336\/image-150.png\" alt=\"\" class=\"wp-image-651157\"\/><\/figure>\n\n\n\n<p>Opa, e agora? Temos uma equa\u00e7\u00e3o e 2 vari\u00e1veis. Essa f\u00f3rmula n\u00e3o d\u00e1, vamos para outra. Sabemos que a dist\u00e2ncia da descida \u00e9 igual a dist\u00e2ncia da subida (5m).<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"260\" height=\"193\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103348\/image-151.png\" alt=\"\" class=\"wp-image-651158\"\/><\/figure>\n\n\n\n<p>Utilize a 3\u00aa f\u00f3rmula e tente descobrir a velocidade final do proj\u00e9til ao tocar o solo (resp.: 10 m\/2)<\/p>\n\n\n\n<div class=\"wp-block-group has-very-light-gray-to-cyan-bluish-gray-gradient-background has-background has-global-padding is-layout-constrained wp-block-group-is-layout-constrained\">\n<div style=\"height:18px\" aria-hidden=\"true\" class=\"wp-block-spacer\"><\/div>\n\n\n\n<p><strong><em>Leia tamb\u00e9m:<\/em><\/strong><\/p>\n\n\n\n<div class=\"wp-block-group has-global-padding is-layout-constrained wp-block-group-is-layout-constrained\">\n<ul class=\"wp-block-list\">\n<li><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/com-quantos-anos-posso-fazer-o-concurso-prf\/\" target=\"_blank\" rel=\"noreferrer noopener\">Com quantos anos posso fazer o concurso da PRF?<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/nota-de-corte-prf\/\" target=\"_blank\" rel=\"noreferrer noopener\">Concurso PRF: Qual a nota de corte dos \u00faltimos editais?<\/a><\/li>\n<\/ul>\n\n\n\n<div style=\"height:18px\" aria-hidden=\"true\" class=\"wp-block-spacer\"><\/div>\n<\/div>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-observacao-sobre-lancamento-obliquo\">OBSERVA\u00c7\u00c3O SOBRE LAN\u00c7AMENTO OBL\u00cdQUO<\/h2>\n\n\n\n<p>Um lan\u00e7amento obl\u00edquo pode ser <strong>decomposto em 2 movimentos<\/strong>: vertical (onde a acelera\u00e7\u00e3o \u00e9 a gravidade: acelera\u00e7\u00e3o negativa durante a subida e positiva durante a descida) e o movimento horizontal (acelera\u00e7\u00e3o \u00e9 nula: movimento retil\u00edneo uniforme).<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"379\" height=\"211\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103402\/image-152.png\" alt=\"Movimento Obl\u00edquo\" class=\"wp-image-651159\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103402\/image-152.png 379w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103402\/image-152-300x167.png 300w\" sizes=\"auto, (max-width: 379px) 100vw, 379px\" \/><figcaption class=\"wp-element-caption\">Movimento Obl\u00edquo<\/figcaption><\/figure>\n\n\n\n<p>Irei fazer um artigo sobre esse tipo de movimento. Fique ligado.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-velocidade-vetorial\">Velocidade vetorial<\/h2>\n\n\n\n<p>Como se observa na imagem acima, em uma trajet\u00f3ria que n\u00e3o \u00e9 nem totalmente vertical, nem totalmente horizonta, essa velocidade pode ser decomposta em vetores, para que seja poss\u00edvel trabalhar com as equa\u00e7\u00f5es. Assim<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"187\" height=\"60\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103413\/image-153.png\" alt=\"\" class=\"wp-image-651160\"\/><\/figure>\n\n\n\n<p>Al\u00e9m disso, se soubermos o \u00e2ngulo entre o vetor velocidade e a horizontal, podemos aplicar:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"180\" height=\"119\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103422\/image-154.png\" alt=\"\" class=\"wp-image-651161\"\/><\/figure>\n\n\n\n<p>A trajet\u00f3ria vertical (com acelera\u00e7\u00e3o constante), tomar\u00e1 por base exclusivamente a Velocidade y. Por outro lado, a trajet\u00f3ria horizontal (acelera\u00e7\u00e3o numa) tomar\u00e1 por base a Velocidade x.<\/p>\n\n\n\n<p>Em hip\u00f3tese alguma (para movimentos obl\u00edquos) utilize a velocidade resultante. Sempre decomponha em x e em y para utilizar-se das f\u00f3rmulas.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-aceleracao-centripeta\">Acelera\u00e7\u00e3o Centr\u00edpeta<\/h2>\n\n\n\n<p>Quando o movimento for circular, faz-se necess\u00e1rio o c\u00e1lculo da acelera\u00e7\u00e3o tangencial e a centr\u00edpeta. A acelera\u00e7\u00e3o tangencial tem a mesma dire\u00e7\u00e3o da velocidade, por\u00e9m pode ter mesmo sentido (acelera\u00e7\u00e3o) ou sentido inverso (desacelera\u00e7\u00e3o)<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"404\" height=\"233\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103438\/image-155.png\" alt=\"Acelera\u00e7\u00e3o centr\u00edpeta\" class=\"wp-image-651163\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103438\/image-155.png 404w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103438\/image-155-300x173.png 300w\" sizes=\"auto, (max-width: 404px) 100vw, 404px\" \/><figcaption class=\"wp-element-caption\">Acelera\u00e7\u00e3o centr\u00edpeta<\/figcaption><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"169\" height=\"91\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103447\/image-156.png\" alt=\"\" class=\"wp-image-651164\"\/><\/figure>\n\n\n\n<p>J\u00e1 a acelera\u00e7\u00e3o centr\u00edpeta tem dire\u00e7\u00e3o radial, apontada para o centro da curvatura. Sua f\u00f3rmula \u00e9 a seguinte:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"175\" height=\"83\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103457\/image-157.png\" alt=\"\" class=\"wp-image-651165\"\/><\/figure>\n\n\n\n<p>Lembrando tamb\u00e9m que o exerc\u00edcio pode fornecer velocidade angular. Como a velocidade angular \u00e9 dada pela f\u00f3rmula:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"147\" height=\"103\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103514\/image-158.png\" alt=\"\" class=\"wp-image-651166\"\/><\/figure>\n\n\n\n<p>Quando falamos em movimento circular, ou seja, movimento em que a mesma trajet\u00f3ria se repete n vezes, faz sentido falarmos em frequ\u00eancia, ou seja, quantas voltas se faz em 1s.<\/p>\n\n\n\n<p>Para calcularmos a frequ\u00eancia, \u00e9 necess\u00e1rio que saibamos o per\u00edodo (T), que \u00e9 o tempo necess\u00e1rio (em segundos) para se completar uma volta completa. Sabendo o per\u00edodo, a frequ\u00eancia \u00e9 dada por:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"139\" height=\"68\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103541\/image-159.png\" alt=\"\" class=\"wp-image-651168\"\/><\/figure>\n\n\n\n<p>Tamb\u00e9m \u00e9 v\u00e1lido decorar as seguintes f\u00f3rmulas:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"200\" height=\"140\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103550\/image-160.png\" alt=\"\" class=\"wp-image-651169\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-fisica-para-a-prf-transmissao-de-movimentos-circulares\">F\u00edsica para a PRF: Transmiss\u00e3o de movimentos circulares<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-por-contato\">Por contato<\/h3>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"567\" height=\"294\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103600\/image-161.png\" alt=\"Transmiss\u00e3o por contato\" class=\"wp-image-651170\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103600\/image-161.png 567w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103600\/image-161-300x156.png 300w\" sizes=\"auto, (max-width: 567px) 100vw, 567px\" \/><figcaption class=\"wp-element-caption\">Transmiss\u00e3o por contato<\/figcaption><\/figure>\n\n\n\n<p>Nesse caso, as velocidades tangenciais s\u00e3o constantes, uma vez que as engrenagens n\u00e3o deslizam uma na outra:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"292\" height=\"181\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103615\/image-162.png\" alt=\"\" class=\"wp-image-651171\"\/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-transmissao-por-correia\">Transmiss\u00e3o por correia<\/h3>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"477\" height=\"210\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103624\/image-163.png\" alt=\"Transmiss\u00e3o por correia\" class=\"wp-image-651172\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103624\/image-163.png 477w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103624\/image-163-300x132.png 300w\" sizes=\"auto, (max-width: 477px) 100vw, 477px\" \/><figcaption class=\"wp-element-caption\">Transmiss\u00e3o por correia<\/figcaption><\/figure>\n\n\n\n<p>Caso semelhante \u00e0 hip\u00f3tese anterior. Aplica-se, portanto as mesmas f\u00f3rmulas.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-transmissao-por-eixo\">Transmiss\u00e3o por eixo<\/h3>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"567\" height=\"207\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103628\/image-164.png\" alt=\"Transmiss\u00e3o por eixo\" class=\"wp-image-651173\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103628\/image-164.png 567w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103628\/image-164-300x110.png 300w\" sizes=\"auto, (max-width: 567px) 100vw, 567px\" \/><figcaption class=\"wp-element-caption\">Transmiss\u00e3o por eixo<\/figcaption><\/figure>\n\n\n\n<p>Nesse caso, as velocidades angulares s\u00e3o iguais, e n\u00e3o mais as velocidades tangenciais.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"127\" height=\"142\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103637\/image-165.png\" alt=\"\" class=\"wp-image-651174\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-leis-de-newton\">Leis de Newton<\/h2>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-conceito-de-forca\">Conceito de For\u00e7a<\/h3>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"121\" height=\"51\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103654\/image-166.png\" alt=\"\" class=\"wp-image-651176\"\/><\/figure>\n\n\n\n<p>For\u00e7a \u00e9 nada mais nada menos que massa x acelera\u00e7\u00e3o.<\/p>\n\n\n\n<p>Mas existem v\u00e1rios tipos de for\u00e7a, todas baseadas na f\u00f3rmula acima. Uma muito cobrada \u00e9 a for\u00e7a el\u00e1stica<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"142\" height=\"51\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103744\/image-167.png\" alt=\"\" class=\"wp-image-651178\"\/><\/figure>\n\n\n\n<p>Onde k \u00e9 a constante el\u00e1stica e x \u00e9 o deslocamento da mola.<\/p>\n\n\n\n<p>Outra essencial para ser memorizada, \u00e9 a for\u00e7a de atrito:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"132\" height=\"54\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103758\/image-168.png\" alt=\"\" class=\"wp-image-651179\"\/><\/figure>\n\n\n\n<p>Em que <img loading=\"lazy\" decoding=\"async\" width=\"9\" height=\"28\" src=\"\"\/>&nbsp;\u00e9 o coeficiente de atrito e N \u00e9 a normal.<\/p>\n\n\n\n<p>Por fim, temos tamb\u00e9m a for\u00e7a centr\u00edpeta, dada pela f\u00f3rmula:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"312\" height=\"77\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103815\/image-169.png\" alt=\"\" class=\"wp-image-651180\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103815\/image-169.png 312w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103815\/image-169-300x74.png 300w\" sizes=\"auto, (max-width: 312px) 100vw, 312px\" \/><\/figure>\n\n\n\n<p>Quando falamos em for\u00e7a, entramos em dois t\u00f3picos muito exigidos tamb\u00e9m nas provas, que s\u00e3o: Trabalho e Energia.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-trabalho\">Trabalho<\/h2>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"199\" height=\"48\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103825\/image-170.png\" alt=\"\" class=\"wp-image-651181\"\/><\/figure>\n\n\n\n<p>&nbsp;Onde |????\u20d7| representa o m\u00f3dulo da for\u00e7a, |????\u20d7| representa o m\u00f3dulo do vetor deslocamento e q \u00e9 o \u00e2ngulo entre o vetor for\u00e7a e o vetor deslocamento.<\/p>\n\n\n\n<p>&nbsp;E se a For\u00e7a aplicada n\u00e3o for constante o tempo inteiro, como na imagem abaixo:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"567\" height=\"299\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103832\/image-171.png\" alt=\"Trabalho pela \u00c1rea\" class=\"wp-image-651182\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103832\/image-171.png 567w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103832\/image-171-300x158.png 300w\" sizes=\"auto, (max-width: 567px) 100vw, 567px\" \/><figcaption class=\"wp-element-caption\">Trabalho pela \u00c1rea<\/figcaption><\/figure>\n\n\n\n<p>Da\u00ed, basta calcular a \u00e1rea acima da linha horizontal e subtrair pela \u00e1rea abaixo da linha horizontal. O resultado \u00e9 justamente o Trabalho.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-trabalho-da-forca-elastica\">Trabalho da For\u00e7a El\u00e1stica<\/h3>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"127\" height=\"68\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103841\/image-172.png\" alt=\"\" class=\"wp-image-651183\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-energia-cinetica-e-potencial\">Energia Cin\u00e9tica e Potencial<\/h2>\n\n\n\n<p>A f\u00f3rmula da energia cin\u00e9tica \u00e9 a seguinte:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"160\" height=\"74\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103851\/image-173.png\" alt=\"\" class=\"wp-image-651184\"\/><\/figure>\n\n\n\n<p>J\u00e1 a energia potencial \u00e9:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"151\" height=\"53\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103903\/image-174.png\" alt=\"\" class=\"wp-image-651185\"\/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-teoria-da-energia-cinetica\">Teoria da Energia Cin\u00e9tica<\/h3>\n\n\n\n<p>A teoria da energia cin\u00e9tica diz que a varia\u00e7\u00e3o da energia cin\u00e9tica \u00e9 igual ao trabalho realizado. Portanto:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"258\" height=\"85\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103913\/image-175.png\" alt=\"\" class=\"wp-image-651186\"\/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-conservacao-da-energia\">Conserva\u00e7\u00e3o da Energia<\/h3>\n\n\n\n<p>Al\u00e9m disso, n\u00e3o podemos nos esquecer da teoria da conserva\u00e7\u00e3o da energia:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"419\" height=\"106\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103923\/image-176.png\" alt=\"\" class=\"wp-image-651187\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103923\/image-176.png 419w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103923\/image-176-300x76.png 300w\" sizes=\"auto, (max-width: 419px) 100vw, 419px\" \/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-potencia\">Pot\u00eancia<\/h2>\n\n\n\n<p>Pot\u00eancia nada mais \u00e9 que:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"123\" height=\"81\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103932\/image-177.png\" alt=\"\" class=\"wp-image-651188\"\/><\/figure>\n\n\n\n<p>Existe tamb\u00e9m o consenti de Pot\u00eancia instant\u00e2nea:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"137\" height=\"47\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103939\/image-178.png\" alt=\"\" class=\"wp-image-651189\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-impulso\">Impulso<\/h2>\n\n\n\n<p>Aqui entramos no \u00faltimo t\u00f3pico das principais f\u00f3rmulas de f\u00edsica para PRF.<\/p>\n\n\n\n<p>Geralmente <strong>tratam-se de quest\u00f5es um pouco mais complexas<\/strong>, que apresentam grandes n\u00edveis de erros. Portanto, fa\u00e7a bastante exerc\u00edcios sobre os pr\u00f3ximos assuntos para sair na frente dos seus candidatos.<\/p>\n\n\n\n<p>Impulso \u00e9 dado por:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"118\" height=\"33\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103948\/image-179.png\" alt=\"\" class=\"wp-image-651190\"\/><\/figure>\n\n\n\n<p>Agora, se a for\u00e7a n\u00e3o for constante, mas sim vari\u00e1vel, o Impulso pode ser calculado pela \u00e1rea do gr\u00e1fico (\u00e1rea acima da horizontal \u2013 \u00e1rea abaixo).<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"461\" height=\"281\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103953\/image-180.png\" alt=\"Impulso\" class=\"wp-image-651191\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103953\/image-180.png 461w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15103953\/image-180-300x183.png 300w\" sizes=\"auto, (max-width: 461px) 100vw, 461px\" \/><figcaption class=\"wp-element-caption\">Impulso pela \u00c1rea<\/figcaption><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-quantidade-de-movimento\">Quantidade de Movimento<\/h2>\n\n\n\n<p>A f\u00f3rmula \u00e9 simples:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"112\" height=\"56\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15104002\/image-181.png\" alt=\"\" class=\"wp-image-651192\"\/><\/figure>\n\n\n\n<p>Podemos, tamb\u00e9m, relacionar quantidade de movimento com Energia cin\u00e9tica, ficando:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"153\" height=\"81\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15104009\/image-182.png\" alt=\"\" class=\"wp-image-651193\"\/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-teorema-do-impulso\">Teorema do Impulso<\/h3>\n\n\n\n<p>Guarde a seguinte f\u00f3rmula para a prova:<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"281\" height=\"47\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2021\/01\/15104016\/image-183.png\" alt=\"\" class=\"wp-image-651194\"\/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-principais-formulas-de-fisica-para-a-prf\">Principais f\u00f3rmulas de f\u00edsica para a PRF<\/h2>\n\n\n\n<p>Finalizamos por aqui as principais f\u00f3rmulas de f\u00edsica para o <a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concurso-prf\/\" target=\"_blank\" rel=\"noreferrer noopener\">concurso PRF<\/a>. Imprima este artigo e deixe ele de lado para resolver muitas quest\u00f5es.<\/p>\n\n\n\n<p>Apenas pela repeti\u00e7\u00e3o \u00e9 que conseguimos fixar o conte\u00fado e de fato aprender.<\/p>\n\n\n\n<p>Desejo a voc\u00ea uma boa prova. Um grande abra\u00e7o.<\/p>\n\n\n\n<p>Leandro Ricardo M. Silveira<\/p>\n\n\n\n<h2 class=\"wp-block-heading has-text-align-center\" id=\"h-cursos-e-assinaturas\">Cursos e Assinaturas<\/h2>\n\n\n\n<div class=\"container\" id=\"boxes\">\n  <div class=\"row\"> \n\n    <div class=\"col-sm\">\n      <div class=\"banner-prf\" id=\"box-assinatura\">\n        <h2 class=\"titulo-assinatura\">Concurso PRF<\/h2>\n        <p class=\"subtitulo-assinatura\">Conquiste a farda da PRF: Comece sua jornada!<\/p>\n        <div class=\"box-botao\">\n          <a class=\"btn-assinatura\" target=\"_blank\" href=\"https:\/\/www.estrategiaconcursos.com.br\/cursosPorConcurso\/prf-policial-rodoviario-federal\/?utm_source=blog&#038;utm_medium=banner&#038;utm_campaign=prf-fisc\" role=\"button\" rel=\"noopener noreferrer\">INICIAR AGORA<\/a>\n        <\/div>\n      <\/div>\n     \n\n  <\/div>\n<\/div><\/div>\n\n\n\n<div class=\"container\" id=\"boxes\">\n  <div class=\"row\">\n\n    <div class=\"col-sm\">\n      <div class=\"estrategia\" id=\"box-assinatura\">\n        <h3 class=\"titulo-assinatura\">Assinatura Concursos<\/h3>\n        <p class=\"subtitulo-assinatura\">Assinatura de 1 Ano ou 2 Anos<\/p>\n        <div class=\"box-botao\">\n          <a class=\"btn-assinatura\" target=\"_blank\" href=\"https:\/\/www.estrategiaconcursos.com.br\/assinaturas\/?utm_source=blog&#038;utm_medium=banner&#038;utm_campaign=fsc-prf-ass\" role=\"button\" rel=\"noopener noreferrer\">ASSINE AGORA<\/a>\n        <\/div>\n      <\/div>\n     \n    <\/div><\/div><\/div>\n\n\n\n<p class=\"has-text-align-center\"><em>Prepare-se com o melhor material e com quem mais aprova em Concursos P\u00fablicos em todo o pa\u00eds. Assine agora a nossa Assinatura Anual e tenha acesso a todos os nossos cursos.<\/em><\/p>\n\n\n\n<p class=\"has-text-align-center has-medium-font-size\"><em><strong>Fique por dentro de todos os concursos:<\/strong><\/em><\/p>\n\n\n\n<p class=\"has-text-align-center has-very-light-gray-to-cyan-bluish-gray-gradient-background has-background\"><a rel=\"noreferrer noopener\" href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concursos-abertos\/\" target=\"_blank\"><strong>Concursos abertos<\/strong><\/a><\/p>\n\n\n\n<p class=\"has-text-align-center has-very-light-gray-to-cyan-bluish-gray-gradient-background has-background\"><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concursos-2024\/\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>Concursos 2024<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Ol\u00e1, Estrategista. Tudo joia? Hoje iremos falar sobre um assunto que \u00e9 o pesadelo de muitos candidatos que prestam o concurso Pol\u00edcia Rodovi\u00e1ria Federal: F\u00cdSICA para a PRF. Ali\u00e1s, quando o assunto \u00e9 exatas, n\u00fameros, muitos sentem at\u00e9 calafrios. Para quem n\u00e3o me conhece, me chamo Leandro, sou Auditor-Fiscal da SEFAZ-SC, aprovado no \u00faltimo concurso [&hellip;]<\/p>\n","protected":false},"author":1668,"featured_media":1026958,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"post_tipo":"article","footnotes":""},"categories":[1,1988],"tags":[220060,220061],"tax_estado":[219964,219965,219966,219967,219968,219969,219963,219970,219971,219972,219973,219974,219975,219976,219977,219978,219979,219980,219981,219982,219983,219984,219985,219986,219987,219988,219989,219990],"class_list":["post-651138","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cursos-e-concursos","category-policia","tag-fisica-para-prf","tag-formulas","tax_estado-ac","tax_estado-al","tax_estado-am","tax_estado-ap","tax_estado-ba","tax_estado-ce","tax_estado-concursos-federais","tax_estado-df","tax_estado-es","tax_estado-go","tax_estado-ma","tax_estado-mg","tax_estado-ms","tax_estado-mt","tax_estado-pa","tax_estado-pb","tax_estado-pe","tax_estado-pi","tax_estado-pr","tax_estado-rj","tax_estado-rn","tax_estado-ro","tax_estado-rr","tax_estado-rs","tax_estado-sc","tax_estado-se","tax_estado-sp","tax_estado-to"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.2 (Yoast SEO v27.2) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>F\u00edsica para a PRF: F\u00f3rmulas de F\u00edsica para gabaritar na prova!<\/title>\n<meta name=\"description\" content=\"Como melhorar na mat\u00e9ria de f\u00edsica para PRF? 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