{"id":1464007,"date":"2024-09-18T18:03:20","date_gmt":"2024-09-18T21:03:20","guid":{"rendered":"https:\/\/www.estrategiaconcursos.com.br\/blog\/?p=1464007"},"modified":"2024-09-19T10:37:28","modified_gmt":"2024-09-19T13:37:28","slug":"concurso-anatel-recursos-para-ciencias-de-dados","status":"publish","type":"post","link":"https:\/\/www.estrategiaconcursos.com.br\/blog\/concurso-anatel-recursos-para-ciencias-de-dados\/","title":{"rendered":"Concurso ANATEL: recursos para Ci\u00eancias de Dados"},"content":{"rendered":"\n<p>As provas objetivas do&nbsp;<strong>concurso<\/strong> <strong>ANATEL<\/strong> foram aplicadas no \u00faltimo domingo (15\/09) e aqui voc\u00ea poder\u00e1 conferir as sugest\u00f5es de recursos para o cargo de&nbsp;<strong>Especialista em Regula\u00e7\u00e3o de Servi\u00e7os P\u00fablicos de Telecomunica\u00e7\u00f5es &#8211; Ci\u00eancias de Dados.<\/strong><\/p>\n\n\n\n<p>Os recursos foram elaborados pelos professores e especialistas do Estrat\u00e9gia Concursos com base\u00a0neste <a href=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18172926\/anatel-ciencias-de-dados-2.pdf\" target=\"_blank\" rel=\"noreferrer noopener nofollow\">caderno<\/a>.<\/p>\n\n\n\n<p>Lembre-se que o recurso \u00e9 individual e a c\u00f3pia pode resultar na anula\u00e7\u00e3o da sua interposi\u00e7\u00e3o. Confira as sugest\u00f5es na transcri\u00e7\u00e3o logo abaixo!<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-concurso-anatel-nbsp-recursos-para-ciencias-de-dados\">Concurso ANATEL:&nbsp;recursos para Ci\u00eancias de Dados <\/h2>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-questao-56\">Quest\u00e3o 56<\/h3>\n\n\n\n<p><strong>Pedido:<\/strong> troca de gabarito.<br \/><strong>Justificativa<\/strong>: Temos uma distribui\u00e7\u00e3o geom\u00e9trica dada por:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"161\" height=\"24\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173131\/image-393.png\" alt=\"\" class=\"wp-image-1464009\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173131\/image-393.png 161w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173131\/image-393-150x22.png 150w\" sizes=\"auto, (max-width: 161px) 100vw, 161px\" \/><\/figure>\n\n\n\n<p>Para uma amostra de tamanho n, a fun\u00e7\u00e3o de m\u00e1xima verossimilhan\u00e7a ser\u00e1:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"173\" height=\"72\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173146\/image-394.png\" alt=\"\" class=\"wp-image-1464010\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173146\/image-394.png 173w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173146\/image-394-150x62.png 150w\" sizes=\"auto, (max-width: 173px) 100vw, 173px\" \/><\/figure>\n\n\n\n<p>Substituindo a amostra, temos:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"411\" height=\"61\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173203\/image-395.png\" alt=\"\" class=\"wp-image-1464011\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173203\/image-395.png 411w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173203\/image-395-300x45.png 300w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173203\/image-395-150x22.png 150w\" sizes=\"auto, (max-width: 411px) 100vw, 411px\" \/><\/figure>\n\n\n\n<p>Simplificando:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"163\" height=\"40\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173223\/image-396.png\" alt=\"\" class=\"wp-image-1464012\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173223\/image-396.png 163w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173223\/image-396-150x37.png 150w\" sizes=\"auto, (max-width: 163px) 100vw, 163px\" \/><\/figure>\n\n\n\n<p>Aplicaremos logaritmo natural para facilitar o processo,<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"236\" height=\"108\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173239\/image-397.png\" alt=\"\" class=\"wp-image-1464013\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173239\/image-397.png 236w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173239\/image-397-150x69.png 150w\" sizes=\"auto, (max-width: 236px) 100vw, 236px\" \/><\/figure>\n\n\n\n<p>Para encontrar a EMV de p, derivamos a log \u2013 verossimilhan\u00e7a em rela\u00e7\u00e3o a p e igualamos a zero:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"218\" height=\"80\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173305\/image-398.png\" alt=\"\" class=\"wp-image-1464014\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173305\/image-398.png 218w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173305\/image-398-150x55.png 150w\" sizes=\"auto, (max-width: 218px) 100vw, 218px\" \/><\/figure>\n\n\n\n<p>De onde temos que p = 5\/13<\/p>\n\n\n\n<p>Sunstituindo p = 5\/13 na distribui\u00e7\u00e3o, temos que?<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"212\" height=\"72\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173339\/image-399.png\" alt=\"\" class=\"wp-image-1464015\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173339\/image-399.png 212w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173339\/image-399-150x51.png 150w\" sizes=\"auto, (max-width: 212px) 100vw, 212px\" \/><\/figure>\n\n\n\n<p>Agora podemos calcular a m\u00e9dia de W por meio da rela\u00e7\u00e3o:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"137\" height=\"48\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173435\/image-400.png\" alt=\"\" class=\"wp-image-1464017\"\/><\/figure>\n\n\n\n<p>Substituindo P por sua EMV, temos:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"171\" height=\"97\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173449\/image-401.png\" alt=\"\" class=\"wp-image-1464018\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173449\/image-401.png 171w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18173449\/image-401-150x85.png 150w\" sizes=\"auto, (max-width: 171px) 100vw, 171px\" \/><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity is-style-dots\"\/>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-questao-59\">Quest\u00e3o 59<\/h3>\n\n\n\n<p><strong>Pedido:<\/strong> troca de gabarito<br \/><strong>Justificativa:<\/strong> Temos uma distribui\u00e7\u00e3o geom\u00e9trica dada por<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"171\" height=\"33\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18175842\/image-402.png\" alt=\"\" class=\"wp-image-1464021\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18175842\/image-402.png 171w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18175842\/image-402-150x29.png 150w\" sizes=\"auto, (max-width: 171px) 100vw, 171px\" \/><\/figure>\n\n\n\n<p>Para uma amostra de tamanho n, a fun\u00e7\u00e3o de m\u00e1xima verossimilhan\u00e7a ser\u00e1:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"196\" height=\"91\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180036\/image-405.png\" alt=\"\" class=\"wp-image-1464024\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180036\/image-405.png 196w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180036\/image-405-150x70.png 150w\" sizes=\"auto, (max-width: 196px) 100vw, 196px\" \/><\/figure>\n\n\n\n<p>Substituindo a amostra, temos:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"408\" height=\"69\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18175959\/image-404.png\" alt=\"\" class=\"wp-image-1464023\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18175959\/image-404.png 408w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18175959\/image-404-300x51.png 300w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18175959\/image-404-150x25.png 150w\" sizes=\"auto, (max-width: 408px) 100vw, 408px\" \/><\/figure>\n\n\n\n<p>Simplificando:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"151\" height=\"38\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180052\/image-406.png\" alt=\"\" class=\"wp-image-1464025\"\/><\/figure>\n\n\n\n<p>Aplicaremos logaritmo natural para facilitar o processo,<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"239\" height=\"100\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180107\/image-407.png\" alt=\"\" class=\"wp-image-1464026\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180107\/image-407.png 239w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180107\/image-407-150x63.png 150w\" sizes=\"auto, (max-width: 239px) 100vw, 239px\" \/><\/figure>\n\n\n\n<p>Para encontrar a EMV de p, derivamos a log \u2013 verossimilhan\u00e7a em rela\u00e7\u00e3o a p e igualamos a zero:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"215\" height=\"80\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180118\/image-408.png\" alt=\"\" class=\"wp-image-1464027\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180118\/image-408.png 215w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2024\/09\/18180118\/image-408-150x56.png 150w\" sizes=\"auto, (max-width: 215px) 100vw, 215px\" \/><\/figure>\n\n\n\n<p>De onde temos que p = 5\/13<\/p>\n\n\n\n<p class=\"has-text-align-center has-very-light-gray-to-cyan-bluish-gray-gradient-background has-background\"><strong>Saiba mais: <a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concurso-anatel\/\" target=\"_blank\" rel=\"noreferrer noopener\">Concurso ANATEL<\/a><\/strong><\/p>\n\n\n\n<div class=\"container\" id=\"boxes\">\r\n  <div class=\"row\">\r\n\r\n    <div class=\"col-sm\">\r\n      <div class=\"banner-estrategia\" id=\"box-assinatura\">\r\n        <h3 class=\"titulo-assinatura\">Concurso Anatel<\/h3>\r\n        <p class=\"subtitulo-assinatura\">Conhe\u00e7a os cursos<\/p>\r\n        <div class=\"box-botao\">\r\n          <a class=\"btn-assinatura\" target=\"_blank\" href=\"https:\/\/www.estrategiaconcursos.com.br\/cursosPorConcurso\/anatel-77\/\" role=\"button\" rel=\"noopener noreferrer\">Conhe\u00e7a mais<\/a>\r\n        <\/div>\r\n      <\/div><\/div><\/div><\/div>\n\n\n\n<div class=\"container\" id=\"boxes\">\r\n  <div class=\"row\">\r\n\r\n    <div class=\"col-sm\">\r\n      <div class=\"estrategia\" id=\"box-assinatura\">\r\n        <h3 class=\"titulo-assinatura\">Assinatura Concursos<\/h3>\r\n        <p class=\"subtitulo-assinatura\">Assinatura de 1 ano ou 2 anos<\/p>\r\n        <div class=\"box-botao\">\r\n          <a class=\"btn-assinatura\" target=\"_blank\" href=\"https:\/\/www.estrategiaconcursos.com.br\/assinaturas\/\" role=\"button\" rel=\"noopener noreferrer\">ASSINE AGORA<\/a>\r\n        <\/div>\r\n      <\/div><\/div><\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading has-text-align-center\" id=\"h-quer-saber-tudo-sobre-concursos-previstos-confira-nossos-artigos\">Quer saber tudo sobre concursos previstos?<br \/>Confira nossos artigos!<\/h2>\n\n\n\n<ul class=\"wp-block-list\">\n<li><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concursos-abertos\/\" target=\"_blank\" rel=\"noreferrer noopener\">Concursos Abertos<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concursos-agencias-reguladoras\/\" target=\"_blank\" rel=\"noreferrer noopener\">Concursos Ag\u00eancias Reguladoras<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concursos-2024\/\" target=\"_blank\" rel=\"noreferrer noopener\">Concursos 2024<\/a><\/li>\n\n\n\n<li><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concursos-2025\/?srsltid=AfmBOoqoMHuNGeyW_Nk7kEauxdkmNuqY4ONEtD-eo8MGb-aTU0K5rteo\" target=\"_blank\" rel=\"noreferrer noopener\">Concursos 2025<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>As provas objetivas do&nbsp;concurso ANATEL foram aplicadas no \u00faltimo domingo (15\/09) e aqui voc\u00ea poder\u00e1 conferir as sugest\u00f5es de recursos para o cargo de&nbsp;Especialista em Regula\u00e7\u00e3o de Servi\u00e7os P\u00fablicos de Telecomunica\u00e7\u00f5es &#8211; Ci\u00eancias de Dados. Os recursos foram elaborados pelos professores e especialistas do Estrat\u00e9gia Concursos com base\u00a0neste caderno. Lembre-se que o recurso \u00e9 individual [&hellip;]<\/p>\n","protected":false},"author":2903,"featured_media":1020939,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"post_tipo":"news","footnotes":""},"categories":[220215,220219],"tags":[8],"tax_estado":[219963],"class_list":["post-1464007","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-agencia-reguladora","category-noticias","tag-recurso","tax_estado-concursos-federais"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.2 (Yoast SEO v27.2) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Concurso ANATEL: recursos para Ci\u00eancias de Dados<\/title>\n<meta name=\"description\" content=\"Confira os poss\u00edveis recursos para o cargo de Especialista em Regula\u00e7\u00e3o de Servi\u00e7os P\u00fablicos de Telecomunica\u00e7\u00f5es - Ci\u00eancia de Dados!\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concurso-anatel-recursos-para-ciencias-de-dados\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Concurso ANATEL: recursos para Ci\u00eancias de Dados\" \/>\n<meta property=\"og:description\" content=\"Confira os poss\u00edveis recursos para o cargo de Especialista em Regula\u00e7\u00e3o de Servi\u00e7os P\u00fablicos de Telecomunica\u00e7\u00f5es - 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