{"id":1195498,"date":"2023-04-14T14:00:00","date_gmt":"2023-04-14T17:00:00","guid":{"rendered":"https:\/\/www.estrategiaconcursos.com.br\/blog\/?p=1195498"},"modified":"2023-04-04T16:46:34","modified_gmt":"2023-04-04T19:46:34","slug":"tj-sp-nocoes-geometria","status":"publish","type":"post","link":"https:\/\/www.estrategiaconcursos.com.br\/blog\/tj-sp-nocoes-geometria\/","title":{"rendered":"Matem\u00e1tica para TJ-SP: No\u00e7\u00f5es de Geometria"},"content":{"rendered":"\n<p>Confira neste artigo as principais <strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">no\u00e7\u00f5es de geometria<\/mark><\/strong>, da disciplina de <strong>Matem\u00e1tica<\/strong>, para o concurso do TJ-SP.<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31193230\/image-481.png\" alt=\"Matem\u00e1tica para TJ-SP: No\u00e7\u00f5es de Geometria\" class=\"wp-image-1195500\" width=\"303\" height=\"315\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31193230\/image-481.png 261w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31193230\/image-481-150x156.png 150w\" sizes=\"auto, (max-width: 303px) 100vw, 303px\" \/><\/figure>\n\n\n\n<p>Este artigo \u00e9 para voc\u00ea que vai prestar o concurso do TJ-SP e est\u00e1 receoso com a disciplina de <strong>Matem\u00e1tica<\/strong>. Venha conosco e aprenda os principais t\u00f3picos desta disciplina para o seu concurso. E o artigo de hoje \u00e9 sobre <strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">No\u00e7\u00f5es de Geometria<\/mark><\/strong>, para o TJ-SP.<\/p>\n\n\n\n<p>Vale destacar que o&nbsp;<a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concurso-tj-sp\/\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>TJ-SP<\/strong><\/a>&nbsp;est\u00e1 com dois editais abertos, para o cargo de&nbsp;<strong>Escrevente<\/strong>, com remunera\u00e7\u00e3o inicial podendo chegar a R$ 7.209,16.<\/p>\n\n\n\n<p>Vamos l\u00e1!<\/p>\n\n\n\n<div class=\"container\" id=\"boxes\">\n  <div class=\"row\">\n\n    <div class=\"col-sm\">\n      <div class=\"banner-tribunal\" id=\"box-assinatura\">\n        <h3 class=\"titulo-assinatura\">Curso TJ SP<\/h3>\n        <p class=\"subtitulo-assinatura\">Conhe\u00e7a os cursos<\/p>\n        <div class=\"box-botao\">\n          <a class=\"btn-assinatura\" target=\"_blank\" href=\"https:\/\/www.estrategiaconcursos.com.br\/cursosPorConcurso\/tj-sp-escrevente\/\" role=\"button\" rel=\"noopener noreferrer\">Conhe\u00e7a mais<\/a>\n        <\/div>\n      <\/div>\n      <p class=\"texto-auxiliar\">Prepare-se com o melhor material e com quem mais aprova em Concursos P\u00fablicos em todo o pa\u00eds.<\/p>\n    <\/div>\n\n  <\/div>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-perimetro\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">Per\u00edmetro<\/mark><\/h2>\n\n\n\n<p>Vamos come\u00e7ar o nosso artigo com um dos assuntos mais b\u00e1sicos da geometria, o per\u00edmetro.<\/p>\n\n\n\n<p>Per\u00edmetro \u00e9 a <strong>medida do contorno<\/strong> de uma forma bidimensional. Em outras palavras, \u00e9 a <strong>soma do comprimento de todos os lados<\/strong> de uma forma geom\u00e9trica.<\/p>\n\n\n\n<p>Assim, em um <strong>quadrado <\/strong>de lado tamanho L, o seu per\u00edmetro ser\u00e1 L+ L+ L+ L = <strong>4L<\/strong>.<\/p>\n\n\n\n<p>J\u00e1 o per\u00edmetro de um<strong> tri\u00e2ngulo equil\u00e1tero<\/strong> de lado L ser\u00e1 L + L + L = <strong>3L<\/strong>.<\/p>\n\n\n\n<p>No caso de um <strong>c\u00edrculo de raio R<\/strong>, o seu per\u00edmetro \u00e9 chamado de circunfer\u00eancia, sendo ele calculado por <strong>2\u03c0R<\/strong><em><strong>.<\/strong><\/em><\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-red-color\">PI<\/mark><\/strong>: O valor de \u03c0 pode ser definido, para c\u00e1lculos em prova, como 3,14.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-area\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">\u00c1rea<\/mark><\/h2>\n\n\n\n<p>A \u00e1rea, por sua vez, \u00e9 a <strong>medida da superf\u00edcie<\/strong> da figura geom\u00e9trica, geralmente calculada por mm\u00b2, cm\u00b2, m\u00b2, km\u00b2.<\/p>\n\n\n\n<p>Cada forma geom\u00e9trica possui a sua maneira de calcular a sua \u00e1rea. Iremos analisar abaixo as \u00e1reas da principais formas geom\u00e9tricas.<\/p>\n\n\n\n<p>No caso de um <strong>ret\u00e2ngulo<\/strong>, de altura <strong>a<\/strong> e base <strong>b<\/strong>, como visto abaixo, a sua \u00e1rea \u00e9 a multiplica\u00e7\u00e3o desses dois valores: <strong>a x b<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"287\" height=\"165\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200533\/image-482.png\" alt=\"\u00c1rea ret\u00e2ngulo\" class=\"wp-image-1195504\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200533\/image-482.png 287w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200533\/image-482-150x86.png 150w\" sizes=\"auto, (max-width: 287px) 100vw, 287px\" \/><\/figure>\n\n\n\n<p>No caso de um <strong>quadrado<\/strong>, o c\u00e1lculo \u00e9 similar ao de cima. Como os seus lados s\u00e3o iguais, ent\u00e3o a sua \u00e1rea \u00e9 a x a = <strong>a\u00b2<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"188\" height=\"175\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200601\/image-483.png\" alt=\"\u00c1rea quadrado\" class=\"wp-image-1195505\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200601\/image-483.png 188w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200601\/image-483-150x140.png 150w\" sizes=\"auto, (max-width: 188px) 100vw, 188px\" \/><\/figure>\n\n\n\n<p>No caso de uma <strong>circunfer\u00eancia <\/strong>de raio r, temos que a sua \u00e1rea \u00e9 <strong>\u03c0r\u00b2<\/strong><em>.<\/em><\/p>\n\n\n\n<p>Por fim, vamos analisar a \u00e1rea do <strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">tri\u00e2ngulo<\/mark><\/strong>.<\/p>\n\n\n\n<p>O tri\u00e2ngulo pode ser de tr\u00eas tipos:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Equil\u00e1tero<\/strong>: todos os lados iguais.<\/li>\n\n\n\n<li><strong>Is\u00f3sceles<\/strong>: dois lados iguais e um diferente.<\/li>\n\n\n\n<li><strong>Escaleno<\/strong>: tr\u00eas lados diferentes.<\/li>\n<\/ul>\n\n\n\n<p>Al\u00e9m disso, h\u00e1 tamb\u00e9m os chamados <strong>tri\u00e2ngulos ret\u00e2ngulos,<\/strong> que s\u00e3o aqueles que possuem um \u00e2ngulo de 90\u00ba, como na figura abaixo:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"299\" height=\"154\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200720\/image-485.png\" alt=\"\u00e1rea tri\u00e2ngulo\" class=\"wp-image-1195507\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200720\/image-485.png 299w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200720\/image-485-150x77.png 150w\" sizes=\"auto, (max-width: 299px) 100vw, 299px\" \/><\/figure>\n\n\n\n<p>A f\u00f3rmula geral para a \u00e1rea do tri\u00e2ngulo \u00e9:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"129\" height=\"53\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31200916\/image-488.png\" alt=\"\u00e1rea tri\u00e2ngulo\" class=\"wp-image-1195510\"\/><\/figure>\n\n\n\n<p>Assim, a \u00e1rea de um <strong>tri\u00e2ngulo ret\u00e2ngulo<\/strong>, como o visto <strong>acima<\/strong>, ser\u00e1:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"60\" height=\"57\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31202743\/image-507.png\" alt=\"\u00e1rea tri\u00e2ngulo\" class=\"wp-image-1195540\"\/><\/figure>\n\n\n\n<p>No caso de um <strong>tri\u00e2ngulo n\u00e3o ret\u00e2ngulo<\/strong>, como o visto <strong>abaixo<\/strong>, a sua \u00e1rea ser\u00e1:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"57\" height=\"61\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201002\/image-490.png\" alt=\"\u00e1rea tri\u00e2ngulo\" class=\"wp-image-1195512\"\/><\/figure>\n\n\n\n<p> <img loading=\"lazy\" decoding=\"async\" width=\"18\" height=\"27\" src=\"\"\/><\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"384\" height=\"208\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201016\/image-491.png\" alt=\"\u00e1rea tri\u00e2ngulo\" class=\"wp-image-1195513\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201016\/image-491.png 384w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201016\/image-491-300x163.png 300w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201016\/image-491-150x81.png 150w\" sizes=\"auto, (max-width: 384px) 100vw, 384px\" \/><\/figure>\n\n\n\n<p>Contudo, quando houver um<strong> tri\u00e2ngulo equil\u00e1tero<\/strong>, \u00e9 poss\u00edvel encontrar uma f\u00f3rmula espec\u00edfica, derivada da f\u00f3rmula geral acima:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"64\" height=\"68\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201123\/image-495.png\" alt=\"\u00e1rea tri\u00e2ngulo\" class=\"wp-image-1195517\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"388\" height=\"313\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201111\/image-494.png\" alt=\"\u00e1rea tri\u00e2ngulo\" class=\"wp-image-1195516\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201111\/image-494.png 388w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201111\/image-494-300x242.png 300w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201111\/image-494-150x121.png 150w\" sizes=\"auto, (max-width: 388px) 100vw, 388px\" \/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-volume\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">Volume<\/mark><\/h2>\n\n\n\n<p>Os volumes s\u00e3o calculados em rela\u00e7\u00e3o a formas tridimensionais, tamb\u00e9m chamados de <strong>poliedros<\/strong>, como cubos, esferas pir\u00e2mides, entre outros.<\/p>\n\n\n\n<p>Vamos listar as f\u00f3rmulas dos volumes das principais figuras geom\u00e9tricas, para a sua prova.<\/p>\n\n\n\n<p>Primeiramente, vamos aprender a calcular o volume de <strong>prismas<\/strong>.<\/p>\n\n\n\n<p>Prismas s\u00e3o poliedros que possuem <strong>duas bases paralelas distintas<\/strong>, como as figuras abaixo:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201207\/image-496.png\" alt=\"\" class=\"wp-image-1195518\" width=\"253\" height=\"171\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201207\/image-496.png 353w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201207\/image-496-300x202.png 300w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201207\/image-496-150x101.png 150w\" sizes=\"auto, (max-width: 253px) 100vw, 253px\" \/><\/figure>\n\n\n\n<p>Assim, um paralelep\u00edpedo e um cubo tamb\u00e9m s\u00e3o prismas.<\/p>\n\n\n\n<p>Para calcular o volume dessas figuras, usa-se a f\u00f3rmula<strong> \u00e1rea da<\/strong> <strong>base x altura.<\/strong><\/p>\n\n\n\n<p>Dessa maneira, o <strong>volume <\/strong>de um <strong>paralelep\u00edpedo<\/strong> mostrado abaixo \u00e9 <strong>a x b x c<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201306\/image-497.png\" alt=\"\" class=\"wp-image-1195520\" width=\"193\" height=\"278\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201306\/image-497.png 253w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201306\/image-497-209x300.png 209w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201306\/image-497-150x216.png 150w\" sizes=\"auto, (max-width: 193px) 100vw, 193px\" \/><\/figure>\n\n\n\n<p>J\u00e1 o volume de um <strong>cubo <\/strong>de lado a \u00e9 a x a x a = <strong>a\u00b3<\/strong>, como visto abaixo:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201413\/image-498.png\" alt=\"\" class=\"wp-image-1195523\" width=\"222\" height=\"179\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201413\/image-498.png 286w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201413\/image-498-150x121.png 150w\" sizes=\"auto, (max-width: 222px) 100vw, 222px\" \/><\/figure>\n\n\n\n<p>Em rela\u00e7\u00e3o \u00e0s <strong>pir\u00e2mides<\/strong>, temos que os seus volumes s\u00e3o: <\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"67\" height=\"66\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201435\/image-500.png\" alt=\"\" class=\"wp-image-1195525\"\/><\/figure>\n\n\n\n<p>Ab \u00e9 a \u00e1rea da base, sendo h a sua altura.<\/p>\n\n\n\n<p>Essa f\u00f3rmula \u00e9 v\u00e1lida para pir\u00e2mides de qualquer forma geom\u00e9trica da base, como visto abaixo:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201456\/image-501.png\" alt=\"\" class=\"wp-image-1195526\" width=\"389\" height=\"133\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201456\/image-501.png 797w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201456\/image-501-300x102.png 300w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201456\/image-501-768x262.png 768w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201456\/image-501-610x208.png 610w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201456\/image-501-150x51.png 150w\" sizes=\"auto, (max-width: 389px) 100vw, 389px\" \/><\/figure>\n\n\n\n<p>Por fim, o volume de uma <strong>esfera <\/strong>de raio R \u00e9 calculado por:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"50\" height=\"58\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201612\/image-503.png\" alt=\"\" class=\"wp-image-1195528\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201624\/image-504.png\" alt=\"\" class=\"wp-image-1195529\" width=\"184\" height=\"188\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201624\/image-504.png 306w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201624\/image-504-293x300.png 293w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201624\/image-504-150x153.png 150w\" sizes=\"auto, (max-width: 184px) 100vw, 184px\" \/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-teorema-de-pitagoras\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">Teorema de Pit\u00e1goras<\/mark><\/h2>\n\n\n\n<p>O Teorema de Pit\u00e1goras, um dos mais famosos teoremas da matem\u00e1tica, diz o seguinte:<\/p>\n\n\n\n<p class=\"has-text-align-center\"><em>\u201cA soma dos quadrados dos catetos \u00e9 igual ao quadrado da hipotenusa.\u201d<\/em><\/p>\n\n\n\n<p>Mas o que s\u00e3o <strong>catetos <\/strong>e <strong>hipotenusa<\/strong>?<\/p>\n\n\n\n<p>Bom, primeiramente, devemos destacar que este teorema \u00e9 utilizado em <strong>tri\u00e2ngulos ret\u00e2ngulos<\/strong>, como o visto abaixo:<\/p>\n\n\n\n<figure class=\"wp-block-image aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"299\" height=\"154\" src=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201717\/image-505.png\" alt=\"\" class=\"wp-image-1195530\" srcset=\"https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201717\/image-505.png 299w, https:\/\/dhg1h5j42swfq.cloudfront.net\/2023\/03\/31201717\/image-505-150x77.png 150w\" sizes=\"auto, (max-width: 299px) 100vw, 299px\" \/><\/figure>\n\n\n\n<p>Assim, os <strong>catetos <\/strong>s\u00e3o lados do tri\u00e2ngulo <strong>adjacentes <\/strong>ao <strong>\u00e2ngulo de 90\u00ba graus<\/strong>, ou seja, <strong>b<\/strong> e <strong>c<\/strong>, enquanto que a <strong>hipotenusa<\/strong> \u00e9 o lado <strong>oposto <\/strong>ao \u00e2ngulo de 90\u00ba, ou seja, o lado <strong>a<\/strong>.<\/p>\n\n\n\n<p>Dessa maneira, o que o Teorema de Pit\u00e1goras diz \u00e9 que <strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">a\u00b2 = b\u00b2 + c\u00b2<\/mark><\/strong>.<\/p>\n\n\n\n<p>Assim, sabendo o comprimento de dois dos tr\u00eas lados de um tri\u00e2ngulo ret\u00e2ngulo, \u00e9 poss\u00edvel encontrar o comprimento do terceiro lado, utilizando a f\u00f3rmula citada.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-finalizando\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-vivid-cyan-blue-color\">Finalizando<\/mark><\/h2>\n\n\n\n<p>Pessoal, finalizamos o nosso artigo no\u00e7\u00f5es de geometria, da disciplina de Matem\u00e1tica, para o concurso do TJ-SP.<\/p>\n\n\n\n<p>Esperamos que tenham gostado.<\/p>\n\n\n\n<p>Caso queira se preparar para chegar&nbsp;<strong>competitivo&nbsp;<\/strong>nesta prova, invista nos&nbsp;<a href=\"https:\/\/www.estrategiaconcursos.com.br\/cursosPorConcurso\/tj-sp-escrevente\/\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>cursos para o TJ-SP do Estrat\u00e9gia Concursos<\/strong><\/a>. L\u00e1 voc\u00ea encontrar\u00e1&nbsp;<strong>aulas completas e detalhadas, com os melhores professores do mercado<\/strong>,&nbsp;de todos os t\u00f3picos exigidos no edital deste concurso.<\/p>\n\n\n\n<p>Conhe\u00e7a tamb\u00e9m o&nbsp;<a href=\"https:\/\/questoes.estrategiaconcursos.com.br\/\" target=\"_blank\" rel=\"noreferrer noopener\"><strong>Sistema de Quest\u00f5es do Estrat\u00e9gia<\/strong><\/a>. Afinal, a \u00fanica maneira de&nbsp;<strong>consolidar o conte\u00fado&nbsp;<\/strong>de maneira satisfat\u00f3ria \u00e9 atrav\u00e9s da&nbsp;<strong>resolu\u00e7\u00e3o de quest\u00f5es.<\/strong><\/p>\n\n\n\n<p>Bons estudos a todos e at\u00e9 a pr\u00f3xima!<\/p>\n\n\n\n<h2 class=\"wp-block-heading has-text-align-center\" id=\"h-cursos-e-assinaturas\">Cursos e Assinaturas <\/h2>\n\n\n\n<p>Prepare-se com o melhor material e com quem mais aprova em Concursos P\u00fablicos em todo o pa\u00eds!<\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-cyan-blue-color has-text-color has-background\" style=\"background-color:#0078bd\"><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concursos-abertos\/\" target=\"_blank\" rel=\"noreferrer noopener\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-white-color\">Concursos Abertos<\/mark><\/strong><\/a><\/p>\n\n\n\n<p class=\"has-text-align-center has-vivid-cyan-blue-color has-text-color has-background\" style=\"background-color:#0078bd\"><a href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/concursos-2023\/\" target=\"_blank\" rel=\"noreferrer noopener\"><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-white-color\">Concursos 2023<\/mark><\/strong><\/a><\/p>\n\n\n\n<div class=\"container\" id=\"boxes\">\n  <div class=\"row\">\n    <div class=\"col-sm\">\n      <div class=\"estrategia\" id=\"box-assinatura\">\n        <h3 class=\"titulo-assinatura\">Assinatura de Concursos<\/h3>\n        <p class=\"subtitulo-assinatura\">Assinatura de 1 ano ou 2 anos<\/p>\n        <div class=\"box-botao\">\n          <a class=\"btn-assinatura\" target=\"_blank\" href=\"https:\/\/www.estrategiaconcursos.com.br\/assinaturas\/\" role=\"button\" rel=\"noopener noreferrer\">ASSINE AGORA<\/a>\n        <\/div>\n      <\/div>\n      \n    <\/div><\/div><\/div>\n\n\n\n<div class=\"container\" id=\"boxes\">\n  <div class=\"row\">\n\n    <div class=\"col-sm\">\n      <div class=\"banner-tribunal\" id=\"box-assinatura\">\n        <h3 class=\"titulo-assinatura\">Curso TJ SP<\/h3>\n        <p class=\"subtitulo-assinatura\">Conhe\u00e7a os cursos<\/p>\n        <div class=\"box-botao\">\n          <a class=\"btn-assinatura\" target=\"_blank\" href=\"https:\/\/www.estrategiaconcursos.com.br\/cursosPorConcurso\/tj-sp-escrevente\/\" role=\"button\" rel=\"noopener noreferrer\">Conhe\u00e7a mais<\/a>\n        <\/div>\n      <\/div>\n      <p class=\"texto-auxiliar\">Prepare-se com o melhor material e com quem mais aprova em Concursos P\u00fablicos em todo o pa\u00eds.<\/p>\n    <\/div>\n\n  <\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Confira neste artigo as principais no\u00e7\u00f5es de geometria, da disciplina de Matem\u00e1tica, para o concurso do TJ-SP. Este artigo \u00e9 para voc\u00ea que vai prestar o concurso do TJ-SP e est\u00e1 receoso com a disciplina de Matem\u00e1tica. Venha conosco e aprenda os principais t\u00f3picos desta disciplina para o seu concurso. E o artigo de hoje [&hellip;]<\/p>\n","protected":false},"author":1976,"featured_media":1192135,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"post_tipo":"article","footnotes":""},"categories":[1,1984,220737],"tags":[],"tax_estado":[219963,219989],"class_list":["post-1195498","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-cursos-e-concursos","category-tribunais","category-tribunais-tribunais","tax_estado-concursos-federais","tax_estado-sp"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.2 (Yoast SEO v27.2) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>Matem\u00e1tica para TJ-SP: No\u00e7\u00f5es de Geometria<\/title>\n<meta name=\"description\" content=\"Confira neste artigo as principais no\u00e7\u00f5es de geometria, da disciplina de Matem\u00e1tica, para o concurso do TJ-SP.\" \/>\n<meta name=\"robots\" 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