{"id":111328,"date":"2018-03-14T10:26:51","date_gmt":"2018-03-14T13:26:51","guid":{"rendered":"https:\/\/www.estrategiaconcursos.com.br\/blog\/?p=111328"},"modified":"2018-09-21T15:09:44","modified_gmt":"2018-09-21T18:09:44","slug":"raciocinio-logico-abin-agente-de-inteligencia-prova-resolvida","status":"publish","type":"post","link":"https:\/\/www.estrategiaconcursos.com.br\/blog\/raciocinio-logico-abin-agente-de-inteligencia-prova-resolvida\/","title":{"rendered":"Racioc\u00ednio L\u00f3gico ABIN (Agente de Intelig\u00eancia) – prova resolvida"},"content":{"rendered":"

Caros alunos,<\/p>\n

Vejam a seguir a prova de Racioc\u00ednio L\u00f3gico do cargo Agente de Intelig\u00eancia da ABIN resolvida. N\u00e3o encontrei possibilidades de recursos, ok?<\/p>\n

Para ver as figuras das quest\u00f5es, entre em:<\/p>\n

http:\/\/www.cespe.unb.br\/concursos\/ABIN_17\/arquivos\/378_ABIN_CB3_01.PDF<\/p>\n

CESPE \u2013 ABIN \u2013 2018)\u00a0<\/strong>As tr\u00eas figuras precedentes, cada uma com diversos s\u00edmbolos, foram desenhadas na parede de um suposto esconderijo inimigo. O servi\u00e7o de intelig\u00eancia descobriu que cada um dos s\u00edmbolos representa um algarismo do conjunto {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. Com refer\u00eancia a essas figuras, julgue os itens seguintes.<\/p>\n

( ) Considere que o significado da figura II seja \u201cdata: com dia e m\u00eas, nessa ordem\u201d. Nesse caso, h\u00e1 a possibilidade de pelo menos 7 interpreta\u00e7\u00f5es para essa figura.<\/p>\n

( ) Considere que o significado da figura III seja \u201cdata: com dia, m\u00eas e ano entre 2000 e 2100, nessa ordem\u201d. Nesse caso, h\u00e1 a possibilidade de pelo menos 2 interpreta\u00e7\u00f5es para essa figura.<\/p>\n

( ) Se o significado da figura I for \u201cano do s\u00e9culo passado\u201d, existem pelo menos dois anos que podem estar representados nessa figura.<\/p>\n

RESOLU\u00c7\u00c3O:<\/strong><\/p>\n

( ) Considere que o significado da figura II seja \u201cdata: com dia e m\u00eas, nessa ordem\u201d. Nesse caso, h\u00e1 a possibilidade de pelo menos 7 interpreta\u00e7\u00f5es para essa figura.<\/em><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/em>O quadrado representa o algarismo das dezenas do dia (que pode ir de 0 a 3, afinal temos at\u00e9 31 dias em um m\u00eas), mas ele tamb\u00e9m representa o algarismo das dezenas do m\u00eas (que s\u00f3 pode ser 0 ou 1, afinal temos s\u00f3 12 meses). Logo, temos as seguintes possibilidades:<\/p>\n

– se o quadrado for 0, a estrela pode ir de 1 a 9 (afinal n\u00e3o podemos ter o dia 00). Aqui temos 9 possibilidades, que j\u00e1 supera as 7 deste item e torna ele CERTO.<\/p>\n

– se o quadrado for 1, a estrela pode ir de 0 a 9, nos dando 10 possibilidades.<\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Item CERTO.<\/p>\n

( ) Considere que o significado da figura III seja \u201cdata: com dia, m\u00eas e ano entre 2000 e 2100, nessa ordem\u201d. Nesse caso, h\u00e1 a possibilidade de pelo menos 2 interpreta\u00e7\u00f5es para essa figura. <\/em><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/em>Veja que o ano deve come\u00e7ar com o algarismo 2. Ou seja, fica claro que a seta \u00e9 igual a 2. O tri\u00e2ngulo \u00e9 o primeiro algarismo do m\u00eas, podendo ser 0 ou 1 (afinal temos at\u00e9 12 meses). Entretanto, veja que:<\/p>\n

– se o tri\u00e2ngulo for 0, temos a representa\u00e7\u00e3o 22\/02\/2020, que atende os requisitos do enunciado.<\/p>\n

– se o tri\u00e2ngulo for 1, temos a representa\u00e7\u00e3o 22\/12\/2121, que N\u00c3O atende os requisitos, pois \u00e9 superior a 2100.<\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Logo, o item est\u00e1 ERRADO, pois s\u00f3 temos 1 interpreta\u00e7\u00e3o poss\u00edvel.<\/p>\n

( ) Se o significado da figura I for \u201cano do s\u00e9culo passado\u201d, existem pelo menos dois anos que podem estar representados nessa figura.<\/em><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 O s\u00e9culo passado foi de 1901 a 2000. Portanto, o tri\u00e2ngulo pode representar 1 ou 2, que \u00e9 a casa dos milhares do nosso ano. J\u00e1 o c\u00edrculo pode ser 9 ou 0, que s\u00e3o as possibilidades para o algarismo das centenas de um ano do s\u00e9culo passado. Neste caso, temos:<\/p>\n

– tri\u00e2ngulo 1 e c\u00edrculo 9: ano 1919 \u00e0 OK<\/p>\n

– tri\u00e2ngulo 1 e c\u00edrculo 0: ano 1010 \u00e0 n\u00e3o serve<\/p>\n

– tri\u00e2ngulo 2 e c\u00edrculo 9: ano 2929 \u00e0 n\u00e3o serve<\/p>\n

– tri\u00e2ngulo 2 e c\u00edrculo 0: ano 2020 \u00e0 n\u00e3o serve<\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Veja que somente 1 ano do s\u00e9culo passado pode ser representado. Item ERRADO.<\/p>\n

Resposta: C E E <\/strong><\/p>\n

\u00a0<\/strong><\/p>\n

CESPE \u2013 ABIN \u2013 2018)<\/strong> As seguintes proposi\u00e7\u00f5es l\u00f3gicas formam um conjunto de premissas de um argumento:<\/p>\n

C Se Pedro n\u00e3o \u00e9 m\u00fasico, ent\u00e3o Andr\u00e9 \u00e9 servidor da ABIN.<\/p>\n

C Se Andr\u00e9 \u00e9 servidor da ABIN, ent\u00e3o Carlos n\u00e3o \u00e9 um espi\u00e3o.<\/p>\n

C Carlos \u00e9 um espi\u00e3o.<\/p>\n

A partir dessas premissas, julgue o item a seguir, acerca de l\u00f3gica<\/p>\n

de argumenta\u00e7\u00e3o.<\/p>\n

( ) Se a proposi\u00e7\u00e3o l\u00f3gica \u201cPedro \u00e9 m\u00fasico.\u201d for a conclus\u00e3o desse argumento, ent\u00e3o, as premissas juntamente com essa conclus\u00e3o constituem um argumento v\u00e1lido.<\/p>\n

RESOLU\u00c7\u00c3O:<\/strong><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Podemos assumir que as premissas s\u00e3o todas verdadeiras para tentar encontrar a conclus\u00e3o. Assumindo que Carlos \u00e9 um espi\u00e3o<\/u>, na segunda premissa vemos que o trecho \u201cCarlos n\u00e3o \u00e9 um espi\u00e3o\u201d \u00e9 F, de modo que \u201cAndr\u00e9 \u00e9 servidor da ABIN\u201d deve ser F tamb\u00e9m. Com isso, na primeira premissa, vemos que \u201cAndr\u00e9 \u00e9 servidor da ABIN\u201d \u00e9 F, de modo que \u201cPedro n\u00e3o \u00e9 m\u00fasico\u201d deve ser F tamb\u00e9m, o que nos leva a concluir que Pedro \u00e9 m\u00fasico<\/u>. Portanto, esta \u00e9 uma conclus\u00e3o que torna o argumento v\u00e1lido. Item CERTO.<\/p>\n

Resposta: C<\/strong><\/p>\n

\u00a0<\/strong><\/p>\n

CESPE \u2013 ABIN \u2013 2018)<\/strong> A tabela a seguir mostra as tr\u00eas primeiras colunas das 8 linhas das tabelas verdade das proposi\u00e7\u00f5es P ^ (Q v R) e (P ^ Q) –> R, em que P, Q e R s\u00e3o proposi\u00e7\u00f5es l\u00f3gicas simples.<\/p>\n

Julgue os itens que se seguem, completando a tabela, se necess\u00e1rio.<\/p>\n

( ) \u00a0Na tabela, a coluna referente \u00e0 proposi\u00e7\u00e3o l\u00f3gica P ^ (Q v R), escrita na posi\u00e7\u00e3o horizontal, \u00e9 igual a<\/p>\n

( ) Na tabela, a coluna referente \u00e0 proposi\u00e7\u00e3o l\u00f3gica (P ^ Q) –> R,<\/p>\n

escrita na posi\u00e7\u00e3o horizontal, \u00e9 igual a<\/p>\n

RESOLU\u00c7\u00c3O:<\/strong><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Podemos terminar o preenchimento da tabela-verdade assim:<\/p>\n

P\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Q\u00a0\u00a0\u00a0\u00a0\u00a0 R\u00a0\u00a0\u00a0\u00a0\u00a0 QVR\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 P^Q\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 P^(QVR)\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (P^Q)–>R<\/p>\n

V\u00a0 \u00a0 \u00a0 \u00a0V \u00a0\u00a0\u00a0\u00a0 V\u00a0 \u00a0 \u00a0 \u00a0 \u00a0V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V<\/p>\n

F\u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0 V\u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V<\/p>\n

V\u00a0 \u00a0 \u00a0 \u00a0F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V\u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V<\/p>\n

F\u00a0 \u00a0 \u00a0 \u00a0F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V\u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V<\/p>\n

V\u00a0 \u00a0 \u00a0 \u00a0V\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F<\/p>\n

F\u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 V\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V<\/p>\n

V\u00a0 \u00a0 \u00a0 \u00a0F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 V<\/p>\n

F\u00a0 \u00a0 \u00a0 \u00a0 F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 F\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 V<\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Podemos verificar que os dois itens est\u00e3o CERTOS.<\/p>\n

Resposta: C C<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

Caros alunos, Vejam a seguir a prova de Racioc\u00ednio L\u00f3gico do cargo Agente de Intelig\u00eancia da ABIN resolvida. N\u00e3o encontrei possibilidades de recursos, ok? Para ver as figuras das quest\u00f5es, entre em: http:\/\/www.cespe.unb.br\/concursos\/ABIN_17\/arquivos\/378_ABIN_CB3_01.PDF CESPE \u2013 ABIN \u2013 2018)\u00a0As tr\u00eas figuras precedentes, cada uma com diversos s\u00edmbolos, foram desenhadas na parede de um suposto esconderijo inimigo. […]<\/p>\n","protected":false},"author":48,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"post_tipo":"article","footnotes":""},"categories":[1],"tags":[],"tax_estado":[],"class_list":["post-111328","post","type-post","status-publish","format-standard","hentry","category-cursos-e-concursos"],"acf":[],"yoast_head":"\nRacioc\u00ednio L\u00f3gico ABIN (Agente de Intelig\u00eancia) - prova resolvida<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.estrategiaconcursos.com.br\/blog\/raciocinio-logico-abin-agente-de-inteligencia-prova-resolvida\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Racioc\u00ednio L\u00f3gico ABIN (Agente de Intelig\u00eancia) - prova resolvida\" \/>\n<meta property=\"og:description\" content=\"Caros alunos, Vejam a seguir a prova de Racioc\u00ednio L\u00f3gico do cargo Agente de Intelig\u00eancia da ABIN resolvida. N\u00e3o encontrei possibilidades de recursos, ok? Para ver as figuras das quest\u00f5es, entre em: http:\/\/www.cespe.unb.br\/concursos\/ABIN_17\/arquivos\/378_ABIN_CB3_01.PDF CESPE \u2013 ABIN \u2013 2018)\u00a0As tr\u00eas figuras precedentes, cada uma com diversos s\u00edmbolos, foram desenhadas na parede de um suposto esconderijo inimigo. 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